Questions: b) β̂ = 3x - 1° ω̂ = 11x + 17° β 90 (1)

b) β̂ = 3x - 1° ω̂ = 11x + 17° β 90 (1)
Transcript text: b) $\left\{\begin{array}{l}\hat{\beta}=3 x-1^{\circ} \\ \hat{\omega}=11 x+17^{\circ}\end{array}\right.$ $\beta$ 90 (1)
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Solution

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To solve the given system of equations for \(\beta\) and \(\omega\), we need to substitute the value of \(x\) from one equation into the other. However, the problem statement seems incomplete or unclear. Assuming we need to solve for \(\beta\) when \(x = 90\):

  1. Substitute \(x = 90\) into the equation for \(\hat{\beta}\).
  2. Calculate the value of \(\hat{\beta}\).
Paso 1: Sustituir \( x = 90 \) en la ecuación para \(\hat{\beta}\)

Dada la ecuación para \(\hat{\beta}\): \[ \hat{\beta} = 3x - 1 \] Sustituimos \( x = 90 \): \[ \hat{\beta} = 3(90) - 1 \]

Paso 2: Calcular el valor de \(\hat{\beta}\)

Realizamos la operación: \[ \hat{\beta} = 270 - 1 = 269 \]

Respuesta Final

\[ \boxed{\beta = 269} \]

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