Questions: y=3x+4 y=(1/2)x-1

y=3x+4
y=(1/2)x-1
Transcript text: 18) \[ \begin{array}{l} y=3 x+4 \\ y=\frac{1}{2} x-1 \end{array} \]
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Solution

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Solution Steps

Step 1: Find the intersection point

We are looking for the solution to the system of equations: \begin{align_} \label{eq:1} y &= 3x + 4 \\ y &= \frac{1}{2}x - 1\end{align_} We can set the two expressions for \(y\) equal to each other: \[3x + 4 = \frac{1}{2}x - 1\]

Step 2: Solve for x

Subtract \(\frac{1}{2}x\) from both sides: \[\frac{5}{2}x + 4 = -1\] Subtract 4 from both sides: \[\frac{5}{2}x = -5\] Multiply both sides by \(\frac{2}{5}\): \[x = -5 \cdot \frac{2}{5} = -2\]

Step 3: Solve for y

Substitute \(x = -2\) into the first equation: \[y = 3(-2) + 4 = -6 + 4 = -2\] Substitute \(x = -2\) into the second equation: \[y = \frac{1}{2}(-2) - 1 = -1 - 1 = -2\]

Final Answer

The solution is \(\boxed{x = -2, y = -2}\). The lines intersect at the point \((-2, -2)\).

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