We are looking for the solution to the system of equations:
\begin{align_} \label{eq:1} y &= 3x + 4 \\ y &= \frac{1}{2}x - 1\end{align_}
We can set the two expressions for \(y\) equal to each other:
\[3x + 4 = \frac{1}{2}x - 1\]
Step 2: Solve for x
Subtract \(\frac{1}{2}x\) from both sides:
\[\frac{5}{2}x + 4 = -1\]
Subtract 4 from both sides:
\[\frac{5}{2}x = -5\]
Multiply both sides by \(\frac{2}{5}\):
\[x = -5 \cdot \frac{2}{5} = -2\]
Step 3: Solve for y
Substitute \(x = -2\) into the first equation:
\[y = 3(-2) + 4 = -6 + 4 = -2\]
Substitute \(x = -2\) into the second equation:
\[y = \frac{1}{2}(-2) - 1 = -1 - 1 = -2\]
Final Answer
The solution is \(\boxed{x = -2, y = -2}\). The lines intersect at the point \((-2, -2)\).