Questions: For the function (f(x)=4 x^2), make a table of slopes of secant lines and make a conjecture about the slope of the tangent line at (x=3).
Complete the table.
(Do not round until the final answer. Then round to the nearest thousandth as needed.)
Interval Slope of the Secant Line
------
[2,3] 20
[2.5,3]
Transcript text: For the function $f(x)=4 x^{2}$, make a table of slopes of secant lines and make a conjecture about the slope of the tangent line at $x=3$.
Complete the table.
(Do not round until the final answer. Then round to the nearest thousandth as needed.)
\begin{tabular}{|c|c|}
\hline Interval & \begin{tabular}{c}
Slope of the \\
Secant Line
\end{tabular} \\
\hline$[2,3]$ & 20 \\
\hline$[2.5,3]$ & $\square$ \\
\hline
\end{tabular}
Solution
Solution Steps
Step 1: Define the Function and Calculate Secant Slope
The function given is \( f(x) = 4x^2 \). To find the slope of the secant line over the interval \([2.5, 3]\), we use the formula for the slope of a secant line:
Step 2: Conjecture the Slope of the Tangent Line at \( x = 3 \)
To conjecture the slope of the tangent line at \( x = 3 \), we observe the pattern of the secant slopes as the intervals approach \( x = 3 \). The slope of the secant line over \([2, 3]\) is 20, and over \([2.5, 3]\) is 22. As the interval gets smaller, the slope approaches a certain value.
For a quadratic function \( f(x) = ax^2 \), the derivative \( f'(x) = 2ax \) gives the slope of the tangent line. Here, \( a = 4 \), so:
\[
f'(x) = 8x
\]
At \( x = 3 \):
\[
f'(3) = 8 \times 3 = 24
\]
Final Answer
The slope of the tangent line at \( x = 3 \) is \(\boxed{24}\).