Questions: Right Triangle Trigonometry
Suppose π/2 ≤ θ ≤ π and we obtain the following right triangle:
Compute sin(θ).
with a=21, b=20, and c=29.
20/21
-20/21
21/20
-21/20
20/29
-20/29
29/20
-29/20
21/29
-21/29
29/21
-29/21
Transcript text: Right Triangle Trigonometry
Suppose $\frac{\pi}{2} \leq \theta \leq \pi$ and we obtain the following right triangle:
Compute $\sin (\theta)$.
with $a=21, b=20$, and $c=29$.
$\frac{20}{21}$
$-\frac{20}{21}$
$\frac{21}{20}$
$-\frac{21}{20}$
$\frac{20}{29}$
$-\frac{20}{29}$
$\frac{29}{20}$
$-\frac{29}{20}$
$\frac{21}{29}$
$-\frac{21}{29}$
$\frac{29}{21}$
$-\frac{29}{21}$
Solution
Solution Steps
Step 1: Identify the given values
We are given a right triangle with:
\( a = 21 \)
\( b = 20 \)
\( c = 29 \)
Step 2: Recall the definition of sine
The sine of an angle in a right triangle is defined as the ratio of the length of the opposite side to the hypotenuse. For angle \( \theta \):
\[ \sin(\theta) = \frac{\text{opposite}}{\text{hypotenuse}} \]