Questions: You are conducting a study to see if the proportion of women over 40 who regularly have mammograms is significantly less than 0.38. You use a significance level of α=0.05. H0: p=0.38 H1: p<0.38 You obtain a sample of size n=725 in which there are 259 successes. What is the test statistic for this sample? (Report answer accurate to three decimal places.) test statistic = What is the p-value for this sample? (Report answer accurate to four decimal places.) p-value = The p-value is... less than (or equal to) α greater than α This test statistic leads to a decision to... reject the null accept the null fail to reject the null As such, the final conclusion is that... There is sufficient evidence to warrant rejection of the claim that the proportion of women over 40 who regularly have mammograms is less than 0.38. There is not sufficient evidence to warrant rejection of the claim that the proportion of women over 40 who regularly have mammograms is less than 0.38. The sample data support the claim that the proportion of women over 40 who regularly have mammograms is less than 0.38. There is not sufficient sample evidence to support the claim that the proportion of women over 40 who regularly have mammograms is less than 0.38.

You are conducting a study to see if the proportion of women over 40 who regularly have mammograms is significantly less than 0.38. You use a significance level of α=0.05.

H0: p=0.38
H1: p<0.38

You obtain a sample of size n=725 in which there are 259 successes.
What is the test statistic for this sample? (Report answer accurate to three decimal places.)
test statistic =
What is the p-value for this sample? (Report answer accurate to four decimal places.)
p-value =
The p-value is...
less than (or equal to) α
greater than α

This test statistic leads to a decision to...
reject the null
accept the null
fail to reject the null

As such, the final conclusion is that...
There is sufficient evidence to warrant rejection of the claim that the proportion of women over 40 who regularly have mammograms is less than 0.38.
There is not sufficient evidence to warrant rejection of the claim that the proportion of women over 40 who regularly have mammograms is less than 0.38.
The sample data support the claim that the proportion of women over 40 who regularly have mammograms is less than 0.38.
There is not sufficient sample evidence to support the claim that the proportion of women over 40 who regularly have mammograms is less than 0.38.
Transcript text: You are conducting a study to see if the proportion of women over 40 who regularly have mammograms is significantly less than 0.38 . You use a significance level of $\boldsymbol{\alpha}=\mathbf{0 . 0 5}$. \[ \begin{array}{l} H_{0}: p=0.38 \\ H_{1}: p<0.38 \end{array} \] You obtain a sample of size $n=725$ in which there are 259 successes. What is the test statistic for this sample? (Report answer accurate to three decimal places.) test statistic $=$ $\square$ What is the p-value for this sample? (Report answer accurate to four decimal places.) p -value = $\square$ The $p$-value is... less than (or equal to) $\alpha$ greater than $\alpha$ This test statistic leads to a decision to... reject the null accept the null fail to reject the null As such, the final conclusion is that... There is sufficient evidence to warrant rejection of the claim that the proportion of women over 40 who regularly have mammograms is less than 0.38 . There is not sufficient evidence to warrant rejection of the claim that the proportion of women over 40 who regularly have mammograms is less than 0.38 . The sample data support the claim that the proportion of women over 40 who regularly have mammograms is less than 0.38 . There is not sufficient sample evidence to support the claim that the proportion of women over 40 who regularly have mammograms is less than 0.38 .
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Solution

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Solution Steps

Step 1: Hypothesis Formulation

We are conducting a hypothesis test to determine if the proportion of women over 40 who regularly have mammograms is significantly less than \(0.38\). The hypotheses are formulated as follows:

  • Null Hypothesis: \(H_0: p = 0.38\)
  • Alternative Hypothesis: \(H_1: p < 0.38\)
Step 2: Test Statistic Calculation

The test statistic for the sample proportion is calculated using the formula:

\[ Z = \frac{\hat{p} - p_0}{\sqrt{\frac{p_0(1 - p_0)}{n}}} \]

Where:

  • \(\hat{p} = \frac{259}{725} \approx 0.3572\) (sample proportion)
  • \(p_0 = 0.38\) (hypothesized population proportion)
  • \(n = 725\) (sample size)

Substituting the values, we find:

\[ Z = \frac{0.3572 - 0.38}{\sqrt{\frac{0.38(1 - 0.38)}{725}}} \approx -1.2625 \]

Thus, the test statistic is:

\[ \text{Test statistic} = -1.262 \]

Step 3: P-value Calculation

The p-value associated with the test statistic is calculated. For a left-tailed test, the p-value is given as:

\[ \text{P-value} = 0.1034 \]

Step 4: Decision Making

We compare the p-value to the significance level \(\alpha = 0.05\):

\[ \text{P-value} = 0.1034 > \alpha = 0.05 \]

Since the p-value is greater than \(\alpha\), we fail to reject the null hypothesis.

Step 5: Conclusion

Based on the results, we conclude that there is not sufficient evidence to warrant rejection of the claim that the proportion of women over 40 who regularly have mammograms is less than \(0.38\).

Final Answer

\[ \boxed{\text{Test statistic} = -1.262, \text{ P-value} = 0.1034, \text{ Decision} = \text{fail to reject } H_0} \]

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