Questions: Find the following in radians without a calculator.
[
cos ^-1left(-fracsqrt22right)=
]
Transcript text: Find the following in radians without a calculator.
\[
\cos ^{-1}\left(-\frac{\sqrt{2}}{2}\right)=
\]
$\square$
Type + or -.
Solution
Solution Steps
To find the value of \(\cos^{-1}\left(-\frac{\sqrt{2}}{2}\right)\) in radians, we need to determine the angle whose cosine is \(-\frac{\sqrt{2}}{2}\). We know that \(\cos(\theta) = -\frac{\sqrt{2}}{2}\) at specific angles in the unit circle.
Solution Approach
Identify the reference angle where \(\cos(\theta) = \frac{\sqrt{2}}{2}\).
Determine the angles in the unit circle where the cosine value is negative.
Return the principal value of the inverse cosine function.
Step 1: Identify the Reference Angle
The reference angle where \(\cos(\theta) = \frac{\sqrt{2}}{2}\) is given by:
\[
\theta = \frac{\pi}{4}
\]
Step 2: Determine the Angles with Negative Cosine
The angles in the unit circle where \(\cos(\theta) = -\frac{\sqrt{2}}{2}\) are:
\[
\theta_1 = \pi - \frac{\pi}{4} = \frac{3\pi}{4}
\]
\[
\theta_2 = \pi + \frac{\pi}{4} = \frac{5\pi}{4}
\]
Step 3: Find the Principal Value
The principal value of the inverse cosine function, which is the angle in the range \([0, \pi]\), is:
\[
\cos^{-1}\left(-\frac{\sqrt{2}}{2}\right) = \frac{3\pi}{4}
\]