Questions: What are the coordinates of the corner point where the minimum value of P occurs? Select the correct choice below and fill in any answer boxes present in your choice. A. The coordinates are . (Type an ordered pair.) B. There is no minimum value of P.

What are the coordinates of the corner point where the minimum value of P occurs?
Select the correct choice below and fill in any answer boxes present in your choice.
A. The coordinates are . (Type an ordered pair.)
B. There is no minimum value of P.
Transcript text: What are the coordinates of the corner point where the minimum value of P occurs? Select the correct choice below and fill in any answer boxes present in your choice. A. The coordinates are $\square$ . (Type an ordered pair.) B. There is no minimum value of $P$.
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Solution

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Solution Steps

To find the coordinates of the corner point where the minimum value of \( P \) occurs, we need to identify the feasible region defined by the constraints of the problem. Then, we evaluate the objective function \( P \) at each corner point of this region. The corner point that gives the smallest value of \( P \) is the solution.

Step 1: Define the Objective Function and Constraints

We are given an objective function \( P \) with coefficients \( c = [1, 1] \). This means we want to minimize \( P = x + y \).

The constraints are given by: \[ \begin{align_} x + 2y & \leq 5 \\ 3x + 4y & \leq 6 \end{align_} \] Additionally, the variables \( x \) and \( y \) must be non-negative: \[ x \geq 0, \quad y \geq 0 \]

Step 2: Identify the Feasible Region

The feasible region is defined by the intersection of the constraints: \[ \begin{align_} x + 2y & \leq 5 \\ 3x + 4y & \leq 6 \\ x & \geq 0 \\ y & \geq 0 \end{align_} \]

Step 3: Evaluate the Objective Function at the Corner Points

To find the minimum value of \( P \), we evaluate \( P = x + y \) at each corner point of the feasible region. The corner points are determined by the intersection of the constraints.

Step 4: Determine the Minimum Value

Using the given constraints and bounds, the corner point where the minimum value of \( P \) occurs is found to be at \( (0, 0) \).

Final Answer

\(\boxed{(0, 0)}\)

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