Questions: A spinner has 20 equally sized sections, 8 of which are yellow and 12 of which are red. The spinner is spun and, at the same time, a fair coin is tossed. What is the probability that the spinner lands on yellow and the coin toss is heads?
Transcript text: A spinner has 20 equally sized sections, 8 of which are yellow and 12 of which are red. The spinner is spun and, at the same time, a fair coin is tossed. What is the probability that the spinner lands on yellow and the coin toss is heads?
Do not round your answer.
$\square$
Solution
Solution Steps
Step 1: Determine the probability of the spinner landing on yellow
The spinner has 20 equally sized sections, 8 of which are yellow. The probability \( P(\text{Yellow}) \) of the spinner landing on yellow is:
\[
P(\text{Yellow}) = \frac{\text{Number of yellow sections}}{\text{Total number of sections}} = \frac{8}{20} = \frac{2}{5}.
\]
Step 2: Determine the probability of the coin toss being heads
The coin is fair, so the probability \( P(\text{Heads}) \) of the coin landing on heads is:
\[
P(\text{Heads}) = \frac{1}{2}.
\]
Step 3: Calculate the combined probability
Since the spinner spin and the coin toss are independent events, the probability \( P(\text{Yellow and Heads}) \) of both events occurring simultaneously is the product of their individual probabilities:
\[
P(\text{Yellow and Heads}) = P(\text{Yellow}) \times P(\text{Heads}) = \frac{2}{5} \times \frac{1}{2} = \frac{2}{10} = \frac{1}{5}.
\]