Questions: Find the inverse function (on the given interval, if specified) and graph both f and f^-1 on the same set of axes. Check by looking for the required symmetry in the graphs.
f(x) = √(x-4) for x ≥ 4
Find the inverse function.
f^-1(x) = for x ≥
Transcript text: Find the inverse function (on the given interval, if specified) and graph both $f$ and $f^{-1}$ on the same set of axes. Check by looking for the required symmetry in the graphs.
\[
f(x)=\sqrt{x-4} \text { for } x \geq 4
\]
Find the inverse function.
\[
f^{-1}(x)=\square \text { for } x \geq \square
\]
Solution
Solution Steps
Step 1: Find the Inverse Function
To find the inverse function of \(f(x) = \sqrt{x - 4}\), we solve for \(x\) in terms of \(y\), resulting in \(f^{-1}(x) = \dfrac{x^2 + 4}{1}\).
Step 2: Specify the Domain of the Inverse
The domain of \(f^{-1}\) is the range of \(f\), which starts from \(c = 4\) and extends to infinity or negative infinity, depending on the direction of the domain specified.
Step 3: Graphing
The graph shows both \(f(x)\) and its inverse \(f^{{-1}}(x)\), along with the line \(y = x\) for symmetry check.
Step 4: Check for Symmetry
By observing the graph, we can confirm that \(f(x)\) and \(f^{{-1}}(x)\) are symmetric about the line \(y = x\), verifying the correctness of the inverse function.
Final Answer:
The inverse function of \(f(x) = \sqrt{x - 4}\) is \(f^{-1}(x) = \dfrac{x^2 + 4}{1}\), rounded to 2 decimal places where applicable.