To solve the logarithmic equation \(\log _{4} x-\log _{4}(x-9)=\frac{1}{2}\), we can use the properties of logarithms. First, apply the quotient rule for logarithms to combine the left side into a single logarithm. Then, convert the logarithmic equation into an exponential equation to solve for \(x\).
Step 1: Combine Logarithms
We start with the equation:
\[
\log_{4} x - \log_{4}(x - 9) = \frac{1}{2}
\]
Using the quotient rule for logarithms, we can combine the left side:
\[
\log_{4} \left( \frac{x}{x - 9} \right) = \frac{1}{2}
\]
Step 2: Convert to Exponential Form
Next, we convert the logarithmic equation to its exponential form:
\[
\frac{x}{x - 9} = 4^{\frac{1}{2}}
\]
Since \(4^{\frac{1}{2}} = 2\), we have:
\[
\frac{x}{x - 9} = 2
\]
Step 3: Solve for \(x\)
Now, we can cross-multiply to solve for \(x\):
\[
x = 2(x - 9)
\]
Expanding and rearranging gives:
\[
x = 2x - 18 \implies x - 2x = -18 \implies -x = -18 \implies x = 18
\]
Final Answer
Thus, the solution to the logarithmic equation is:
\[
\boxed{x = 18}
\]