For line L1, we can identify two points: (-1, 0) and (0, 1).
For line L2, we can identify two points: (0, 2) and (2, 0).
The slope \( m \) of a line passing through points \((x_1, y_1)\) and \((x_2, y_2)\) is given by:
\[ m = \frac{y_2 - y_1}{x_2 - x_1} \]
For L1:
\[ m_1 = \frac{1 - 0}{0 - (-1)} = \frac{1}{1} = 1 \]
For L2:
\[ m_2 = \frac{0 - 2}{2 - 0} = \frac{-2}{2} = -1 \]
The equation of a line in slope-intercept form is \( y = mx + b \), where \( m \) is the slope and \( b \) is the y-intercept.
For L1:
Using the point (0, 1):
\[ y = 1x + 1 \]
So, the equation is:
\[ y = x + 1 \]
For L2:
Using the point (0, 2):
\[ y = -1x + 2 \]
So, the equation is:
\[ y = -x + 2 \]
- Equation of L1: \( y = x + 1 \)
- Equation of L2: \( y = -x + 2 \)
- Slope of L1: 1
- Slope of L2: -1
- x-intercept of L1: -1
- y-intercept of L1: 1
- x-intercept of L2: 2
- y-intercept of L2: 2