Questions: Solve the triangle.
A=39°, B=64°, a=5
C=°
b ≈
(Do not round until the final answer. Then round to the nearest tenth as needed.)
c ≈
(Do not round until the final answer. Then round to the nearest tenth as needed.)
Transcript text: Solve the triangle.
\[
\begin{array}{l}
A=39^{\circ}, \quad B=64^{\circ}, \quad a=5 \\
C=\square^{\circ}
\end{array}
\]
$\square$
(Do not round until the final answer. Then round to the nearest degree as needed.)
$\mathrm{b} \approx$ $\square$
(Do not round until the final answer. Then round to the nearest tenth as needed.)
$c \approx$ $\square$
(Do not round until the final answer. Then round to the nearest tenth as needed.)
Solution
Solution Steps
To solve the triangle, we need to find the missing angle \( C \) and the sides \( b \) and \( c \).
Find angle \( C \): Use the fact that the sum of the angles in a triangle is \( 180^\circ \).
Find side \( b \): Use the Law of Sines, which states \(\frac{a}{\sin(A)} = \frac{b}{\sin(B)}\).
Find side \( c \): Again, use the Law of Sines, \(\frac{a}{\sin(A)} = \frac{c}{\sin(C)}\).
Step 1: Find Angle \( C \)
Using the triangle angle sum property, we have:
\[
C = 180^\circ - A - B = 180^\circ - 39^\circ - 64^\circ = 77^\circ
\]
Step 2: Find Side \( b \)
Applying the Law of Sines:
\[
\frac{a}{\sin(A)} = \frac{b}{\sin(B)}
\]
Substituting the known values:
\[
\frac{5}{\sin(39^\circ)} = \frac{b}{\sin(64^\circ)}
\]
Solving for \( b \):
\[
b = 5 \cdot \frac{\sin(64^\circ)}{\sin(39^\circ) } \approx 7.1
\]
Step 3: Find Side \( c \)
Again using the Law of Sines:
\[
\frac{a}{\sin(A)} = \frac{c}{\sin(C)}
\]
Substituting the known values:
\[
\frac{5}{\sin(39^\circ)} = \frac{c}{\sin(77^\circ)}
\]
Solving for \( c \):
\[
c = 5 \cdot \frac{\sin(77^\circ)}{\sin(39^\circ)} \approx 7.7
\]
Final Answer
\[
C = 77^\circ, \quad b \approx 7.1, \quad c \approx 7.7
\]
Thus, the final boxed answers are:
\[
\boxed{C = 77^\circ}, \quad \boxed{b \approx 7.1}, \quad \boxed{c \approx 7.7}
\]