Questions: How many solutions does this system
- have?
- -x+3 y=3
- 2 x-6 y=30
None
One
Infinite
Transcript text: How many solutions does this system
\[
\left\{\begin{array}{c}
\text { have? } \\
-x+3 y=3 \\
2 x-6 y=30
\end{array}\right.
\]
None
One
Infinite
Solution
Solution Steps
Step 1: Rewrite the system of equations
The given system of equations is:
\[
\left\{\begin{array}{c}
-x + 3y = 3 \\
2x - 6y = 30
\end{array}\right.
\]
Step 2: Simplify the second equation
Divide the second equation by 2 to simplify:
\[
x - 3y = 15
\]
Step 3: Compare the two equations
The first equation is:
\[
-x + 3y = 3
\]
The simplified second equation is:
\[
x - 3y = 15
\]
Notice that the left-hand side of the second equation is the negative of the left-hand side of the first equation. This implies:
\[
-x + 3y = 3 \quad \text{and} \quad -(-x + 3y) = 15
\]
\[
-x + 3y = 3 \quad \text{and} \quad x - 3y = 15
\]
These two equations are inconsistent because they cannot be true simultaneously. Therefore, the system has no solution.