Questions: Before being replaced in 2016, a large Ferris wheel on Chicago, Illinois' Navy Pier had a diameter of 140 feet and the riders boarded from a platform 10 feet above the ground. The Ferris wheel completed one rotation every 7 minutes.
Express a rider's height, H, in feet above the ground as a function of time, t, in minutes.
a.) H(t)=-70 sin (2 pi/7 t)+80
b.) H(t)=-70 cos (2 pi/7 t)+80
c.) H(t)=70 cos (2 pi/7 t)+80
d.) H(t)=70 sin (2 pi/7 t)+10
Transcript text: Before being replaced in 2016, a large Ferris wheel on Chicago, Illinois' Navy Pier had a diameter of 140 feet and the riders boarded from a platform 10 feet above the ground. The Ferris wheel completed one rotation every 7 minutes.
Express a rider's height, $H$, in feet above the ground as a function of time, $t$, in minutes.
a.) $H(t)=-70 \sin \left(\frac{2 \pi}{7} t\right)+80$
b.) $H(t)=-70 \cos \left(\frac{2 \pi}{7} t\right)+80$
c.) $H(t)=70 \cos \left(\frac{2 \pi}{7} t\right)+80$
d.) $H(t)=70 \sin \left(\frac{2 \pi}{7} t\right)+10$
Solution
Solution Steps
Step 1: Identify the amplitude and vertical shift
The Ferris wheel has a diameter of 140 feet, so the radius (amplitude) is \( \frac{140}{2} = 70 \) feet. The riders board from a platform 10 feet above the ground, so the vertical shift is \( 70 + 10 = 80 \) feet.
Step 2: Determine the period and angular frequency
The Ferris wheel completes one rotation every 7 minutes, so the period \( T = 7 \) minutes. The angular frequency \( \omega \) is given by:
\[
\omega = \frac{2\pi}{T} = \frac{2\pi}{7}.
\]
Step 3: Choose the correct trigonometric function
The height of the rider starts at the lowest point (10 feet) when \( t = 0 \). This corresponds to a cosine function with a negative amplitude:
\[
H(t) = -70 \cos\left(\frac{2\pi}{7} t\right) + 80.
\]
Step 4: Verify the correct option
The correct function matches option b:
\[
H(t) = -70 \cos\left(\frac{2\pi}{7} t\right) + 80.
\]
Final Answer
The correct answer is B: \( H(t) = -70 \cos \left(\frac{2 \pi}{7} t\right) + 80 \).