Questions: Homework: Section 6.1 Score: 6.5/7 Answered: 6 / 7 Question 7 The Acme Company manufactures widgets. The distribution of widget weights is bell-shaped with a mean of 64 ounces and a standard deviation of 11 ounces. Using the Empirical Rule, answer the following questions. Suggestion: Sketch the distribution. a) 68% of the widget weights lie between and b) What percentage of the widget weights lie between 31 and 75 ounces? % c) What percentage of the widget weights lie below 86 ? % Question Help: Video Submit Question

Homework: Section 6.1
Score: 6.5/7 Answered: 6 / 7

Question 7

The Acme Company manufactures widgets. The distribution of widget weights is bell-shaped with a mean of 64 ounces and a standard deviation of 11 ounces. Using the Empirical Rule, answer the following questions. Suggestion: Sketch the distribution.
a) 68% of the widget weights lie between and 
b) What percentage of the widget weights lie between 31 and 75 ounces?  %
c) What percentage of the widget weights lie below 86 ?  %

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Transcript text: Homework: Section 6.1 Score: 6.5/7 Answered: $6 / 7$ Question 7 The Acme Company manufactures widgets. The distribution of widget weights is bell-shaped with a mean of 64 ounces and a standard deviation of 11 ounces. Using the Empirical Rule, answer the following questions. Suggestion: Sketch the distribution. a) $68 \%$ of the widget weights lie between $\square$ and $\square$ b) What percentage of the widget weights lie between 31 and 75 ounces? $\square$ $\%$ c) What percentage of the widget weights lie below 86 ? $\square$ \% Question Help: $\square$ Video Submit Question
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Solution

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Solution Steps

Step 1: Calculate the Range for 68% of Widget Weights

According to the Empirical Rule, 68%68\% of the data lies within 11 standard deviation of the mean. Given the mean μ=64\mu = 64 ounces and standard deviation σ=11\sigma = 11 ounces, we can calculate the range as follows:

Lower Bound=μσ=6411=53 \text{Lower Bound} = \mu - \sigma = 64 - 11 = 53 Upper Bound=μ+σ=64+11=75 \text{Upper Bound} = \mu + \sigma = 64 + 11 = 75

Thus, 68%68\% of the widget weights lie between 5353 and 7575 ounces.

Step 2: Calculate the Percentage of Widget Weights Between 31 and 75 Ounces

To find the percentage of widget weights between 3131 and 7575 ounces, we calculate the probabilities using the Z-scores:

Zstart=316411=3.0 Z_{start} = \frac{31 - 64}{11} = -3.0 Zend=756411=1.0 Z_{end} = \frac{75 - 64}{11} = 1.0

Using the cumulative distribution function Φ\Phi:

P=Φ(Zend)Φ(Zstart)=Φ(1.0)Φ(3.0)=0.84 P = \Phi(Z_{end}) - \Phi(Z_{start}) = \Phi(1.0) - \Phi(-3.0) = 0.84

Thus, the percentage of widget weights between 3131 and 7575 ounces is:

84.0% 84.0\%

Step 3: Calculate the Percentage of Widget Weights Below 86 Ounces

Next, we calculate the percentage of widget weights below 8686 ounces. The Z-score is calculated as follows:

Zend=866411=2.0 Z_{end} = \frac{86 - 64}{11} = 2.0

Using the cumulative distribution function Φ\Phi:

P=Φ(Zend)Φ()=Φ(2.0)0=0.9772 P = \Phi(Z_{end}) - \Phi(-\infty) = \Phi(2.0) - 0 = 0.9772

Thus, the percentage of widget weights below 8686 ounces is:

97.72% 97.72\%

Final Answer

  • 68%68\% of the widget weights lie between 5353 and 7575 ounces.
  • The percentage of widget weights between 3131 and 7575 ounces is 84.0%84.0\%.
  • The percentage of widget weights below 8686 ounces is 97.72%97.72\%.

\boxed{ \begin{align_} \text{a)} & \quad 53 \text{ and } 75 \\ \text{b)} & \quad 84.0\% \\ \text{c)} & \quad 97.72\% \end{align_} }

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