Questions: Yes or No? (a) If x(x+3) > 0, does it follow that x is positive? Yes No If No, give an example. (If Yes, enter Yes.)

Yes or No?
(a) If x(x+3) > 0, does it follow that x is positive?
Yes
No

If No, give an example. (If Yes, enter Yes.)
Transcript text: Yes or No? (a) If $x(x+3)>0$, does it follow that $x$ is positive? Yes No If No, give an example. (If Yes, enter Yes.)
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Solution

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Solution Steps

To determine if \( x(x+3) > 0 \) implies that \( x \) is positive, we need to analyze the inequality. The product \( x(x+3) \) is positive if both factors are either both positive or both negative. We will check the intervals where this condition holds.

Step 1: Understand the Problem

We need to determine if the inequality \( x(x+3) > 0 \) implies that \( x \) is positive. If the answer is "No," we should provide an example where \( x \) is not positive but the inequality still holds.

Step 2: Analyze the Inequality

The inequality \( x(x+3) > 0 \) can be analyzed by considering the product of two factors:

  1. \( x \)
  2. \( x + 3 \)

For the product \( x(x+3) \) to be greater than zero, both factors must be either both positive or both negative.

Step 3: Determine the Sign of Each Factor
  1. \( x \) is positive if \( x > 0 \).
  2. \( x + 3 \) is positive if \( x > -3 \).
Step 4: Consider the Intervals

We need to consider the intervals where the product \( x(x+3) \) is positive:

  1. Both factors are positive: \( x > 0 \) and \( x + 3 > 0 \) which simplifies to \( x > 0 \).
  2. Both factors are negative: \( x < 0 \) and \( x + 3 < 0 \) which simplifies to \( x < -3 \).
Step 5: Combine the Intervals

The inequality \( x(x+3) > 0 \) holds in the intervals:

  1. \( x > 0 \)
  2. \( x < -3 \)
Step 6: Conclusion

From the intervals, we see that \( x \) can be either greater than 0 or less than -3. Therefore, \( x \) does not have to be positive for the inequality to hold.

Step 7: Provide an Example

An example where \( x \) is not positive but the inequality \( x(x+3) > 0 \) holds is \( x = -4 \): \[ x = -4 \implies (-4)(-4+3) = (-4)(-1) = 4 > 0 \]

Final Answer

\[ \boxed{\text{No}} \]

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