Questions: Yes or No? (a) If x(x+3) > 0, does it follow that x is positive? Yes No If No, give an example. (If Yes, enter Yes.)

Yes or No?
(a) If x(x+3) > 0, does it follow that x is positive?
Yes
No

If No, give an example. (If Yes, enter Yes.)
Transcript text: Yes or No? (a) If $x(x+3)>0$, does it follow that $x$ is positive? Yes No If No, give an example. (If Yes, enter Yes.)
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Solution

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Solution Steps

To determine if x(x+3)>0 x(x+3) > 0 implies that x x is positive, we need to analyze the inequality. The product x(x+3) x(x+3) is positive if both factors are either both positive or both negative. We will check the intervals where this condition holds.

Step 1: Understand the Problem

We need to determine if the inequality x(x+3)>0 x(x+3) > 0 implies that x x is positive. If the answer is "No," we should provide an example where x x is not positive but the inequality still holds.

Step 2: Analyze the Inequality

The inequality x(x+3)>0 x(x+3) > 0 can be analyzed by considering the product of two factors:

  1. x x
  2. x+3 x + 3

For the product x(x+3) x(x+3) to be greater than zero, both factors must be either both positive or both negative.

Step 3: Determine the Sign of Each Factor
  1. x x is positive if x>0 x > 0 .
  2. x+3 x + 3 is positive if x>3 x > -3 .
Step 4: Consider the Intervals

We need to consider the intervals where the product x(x+3) x(x+3) is positive:

  1. Both factors are positive: x>0 x > 0 and x+3>0 x + 3 > 0 which simplifies to x>0 x > 0 .
  2. Both factors are negative: x<0 x < 0 and x+3<0 x + 3 < 0 which simplifies to x<3 x < -3 .
Step 5: Combine the Intervals

The inequality x(x+3)>0 x(x+3) > 0 holds in the intervals:

  1. x>0 x > 0
  2. x<3 x < -3
Step 6: Conclusion

From the intervals, we see that x x can be either greater than 0 or less than -3. Therefore, x x does not have to be positive for the inequality to hold.

Step 7: Provide an Example

An example where x x is not positive but the inequality x(x+3)>0 x(x+3) > 0 holds is x=4 x = -4 : x=4    (4)(4+3)=(4)(1)=4>0 x = -4 \implies (-4)(-4+3) = (-4)(-1) = 4 > 0

Final Answer

No \boxed{\text{No}}

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