To solve the given problem, we need to calculate the mean, median, and mode(s) of the provided data set.
- Mean: Sum all the numbers and divide by the count of numbers.
- Median: Sort the numbers and find the middle value. If the count of numbers is even, take the average of the two middle numbers.
- Mode: Identify the number(s) that appear most frequently in the data set.
The mean of a data set is calculated by summing all the values and dividing by the number of values. Given the data set:
\[ 86, 55, 86, 75, 40, 55, 72, 86, 55 \]
The sum of the values is:
\[ 86 + 55 + 86 + 75 + 40 + 55 + 72 + 86 + 55 = 610 \]
The number of values is:
\[ 9 \]
Thus, the mean is:
\[ \text{Mean} = \frac{610}{9} \approx 67.7778 \]
Rounded to one decimal place:
\[ \text{Mean} \approx 67.8 \]
The median is the middle value of a data set when it is ordered from least to greatest. First, we sort the data set:
\[ 40, 55, 55, 55, 72, 75, 86, 86, 86 \]
Since there are 9 values (an odd number), the median is the middle value:
\[ \text{Median} = 72 \]
The mode is the value(s) that appear most frequently in the data set. From the sorted data set:
\[ 40, 55, 55, 55, 72, 75, 86, 86, 86 \]
We see that both 55 and 86 appear three times, which is more frequent than any other value. Therefore, there are two modes:
\[ \text{Modes} = 55, 86 \]
The number of modes is:
\[ \text{Number of modes} = 2 \]
\[
\boxed{\text{Mean} \approx 67.8}
\]