Questions: Write the equation of a line perpendicular to 4x - 3y = -8 that passes through the point (-4,2).
The equation of the line is y =
(Simplify your answer. Type your answer in slope-intercept form. Use integers or fractions for any numbers in the expression.).
Transcript text: Write the equation of a line perpendicular to $4 x-3 y=-8$ that passes through the point $(-4,2)$.
The equation of the line is $y=$ $\square$
(Simplify your answer. Type your answer in slope-intercept form. Use integers or fractions for any numbers in the expression.).
Solution
Solution Steps
Step 1: Determine the Slope of the Original Line
The original line is given by the equation \(4x - 3y = -8\). To find its slope, we first convert it to the slope-intercept form \(y = mx + b\).
Thus, the slope \(m\) of the original line is \(\frac{4}{3}\).
Step 2: Find the Slope of the Perpendicular Line
The slope of a line perpendicular to another is the negative reciprocal of the original line's slope. Therefore, the slope of the perpendicular line is:
\[
m_{\text{perpendicular}} = -\frac{3}{4}
\]
Step 3: Use the Point-Slope Form to Find the Equation
We use the point-slope form of the equation of a line, \(y - y_1 = m(x - x_1)\), where \((x_1, y_1)\) is the point \((-4, 2)\) through which the perpendicular line passes.
\[
y - 2 = -\frac{3}{4}(x + 4)
\]
Step 4: Simplify to Slope-Intercept Form
Simplifying the equation:
\[
y - 2 = -\frac{3}{4}x - 3
\]
Adding 2 to both sides:
\[
y = -\frac{3}{4}x - 1
\]
Final Answer
The equation of the line perpendicular to \(4x - 3y = -8\) that passes through the point \((-4, 2)\) is: