Questions: Solve for v, (v-5)^2=2 v^2-11 v+13 If there is more than one solution, separate them with commas. v=

Solve for v,
(v-5)^2=2 v^2-11 v+13

If there is more than one solution, separate them with commas.
v=
Transcript text: Solve for $v$, \[ (v-5)^{2}=2 v^{2}-11 v+13 \] If there is more than one solution, separate them with commas. \[ v= \]
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Solution

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Solution Steps

Step 1: Define the Equation

We start with the equation given in the problem: \[ (v - 5)^{2} = 2v^{2} - 11v + 13 \]

Step 2: Rearrange the Equation

To solve for \( v \), we rearrange the equation by moving all terms to one side: \[ (v - 5)^{2} - (2v^{2} - 11v + 13) = 0 \] This simplifies to: \[ -2v^{2} + 11v + (v - 5)^{2} - 13 = 0 \]

Step 3: Factor the Polynomial

The rearranged polynomial can be factored as follows: \[

  • \left(v - 4\right) \left(v + 3\right) = 0 \]
Step 4: Solve for \( v \)

Setting the factored expression equal to zero gives us the solutions: \[ v - 4 = 0 \quad \text{or} \quad v + 3 = 0 \] Thus, we find: \[ v = 4 \quad \text{or} \quad v = -3 \]

Final Answer

The solutions for \( v \) are: \[ \boxed{v = -3, 4} \]

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