Questions: Solve for v,
(v-5)^2=2 v^2-11 v+13
If there is more than one solution, separate them with commas.
v=
Transcript text: Solve for $v$,
\[
(v-5)^{2}=2 v^{2}-11 v+13
\]
If there is more than one solution, separate them with commas.
\[
v=
\]
Solution
Solution Steps
Step 1: Define the Equation
We start with the equation given in the problem:
\[
(v - 5)^{2} = 2v^{2} - 11v + 13
\]
Step 2: Rearrange the Equation
To solve for \( v \), we rearrange the equation by moving all terms to one side:
\[
(v - 5)^{2} - (2v^{2} - 11v + 13) = 0
\]
This simplifies to:
\[
-2v^{2} + 11v + (v - 5)^{2} - 13 = 0
\]
Step 3: Factor the Polynomial
The rearranged polynomial can be factored as follows:
\[
\left(v - 4\right) \left(v + 3\right) = 0
\]
Step 4: Solve for \( v \)
Setting the factored expression equal to zero gives us the solutions:
\[
v - 4 = 0 \quad \text{or} \quad v + 3 = 0
\]
Thus, we find:
\[
v = 4 \quad \text{or} \quad v = -3
\]
Final Answer
The solutions for \( v \) are:
\[
\boxed{v = -3, 4}
\]