We start with the integral
\[ \int \frac{e^{x}}{e^{x}+4} \, dx. \]
We use the substitution \(u = e^{x} + 4\), which gives us \(du = e^{x} \, dx\). This transforms our integral into a simpler form.
After substituting, we find that the integral can be expressed as
\[ \int \frac{du}{u} = \ln|u| + C. \]
Substituting back \(u = e^{x} + 4\), we have
\[ \ln|e^{x} + 4| + C. \]
The original integral can also be expressed in terms of \(e^{x}\):
\[ \int \frac{e^{x}}{e^{x}+4} \, dx = e^{x} - 5 \frac{e^{x}}{e^{x} + 4} + C. \]
This leads us to the final expression for the integral.
Thus, the final answer for the integral is
\[ \boxed{e^{x} - 5 \frac{e^{x}}{e^{x} + 4} + C}. \]
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