Questions: A monatomic ion with a charge of +2 has an electronic configuration of 1s^2 2s^2 2p^6 3s^2 3p^6 4s^2 3d^10 4p^6. This ion is a(n) What is the chemical symbol of the noble gas this ion is isoelectronic with? What is the formula of the ion?

A monatomic ion with a charge of +2 has an electronic configuration of 1s^2 2s^2 2p^6 3s^2 3p^6 4s^2 3d^10 4p^6. This ion is a(n) What is the chemical symbol of the noble gas this ion is isoelectronic with? What is the formula of the ion?
Transcript text: A monatomic ion with a charge of +2 has an electronic configuration of $1 s^{2} 2 s^{2} 2 p^{6} 3 s^{2} 3 p^{6} 4 s^{2} 3 d^{10} 4 p^{6}$. This ion is a(n) $\square$ What is the chemical symbol of the noble gas this ion is isoelectronic with? $\square$ What is the formula of the ion? $\square$
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Solution

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Solution Steps

Step 1: Determine the Element from the Electron Configuration

The given electron configuration is: \[ 1s^2 \, 2s^2 \, 2p^6 \, 3s^2 \, 3p^6 \, 4s^2 \, 3d^{10} \, 4p^6 \]

This configuration corresponds to the noble gas krypton (Kr), which has 36 electrons.

Step 2: Identify the Ion

The ion has a charge of +2, meaning it has lost 2 electrons. Therefore, the neutral atom must have had 38 electrons (36 + 2).

Step 3: Determine the Element with 38 Electrons

The element with 38 electrons is strontium (Sr).

Step 4: Identify the Noble Gas Isoelectronic with the Ion

The ion has the same electron configuration as krypton (Kr), which is a noble gas.

Step 5: Write the Formula of the Ion

The ion is strontium with a +2 charge, so the formula of the ion is \( \text{Sr}^{2+} \).

Final Answer

The ion is a(n) \(\boxed{\text{strontium ion}}\).

The chemical symbol of the noble gas this ion is isoelectronic with is \(\boxed{\text{Kr}}\).

The formula of the ion is \(\boxed{\text{Sr}^{2+}}\).

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