Questions: Decide whether each pair of elements in the table below will form an ionic compound. element #1 element #2 Forms ionic compound? empirical formula of ionic compound --- --- --- --- bromine lithium yes oxygen iodine yes cesium sulfur yes no fluorine calcium yes no

Decide whether each pair of elements in the table below will form an ionic compound. element #1 element #2 Forms ionic compound? empirical formula of ionic compound --- --- --- --- bromine lithium yes oxygen iodine yes cesium sulfur yes no fluorine calcium yes no
Transcript text: Decide whether each pair of elements in the table below will form an ionic compound. \begin{tabular}{|c|c|cc|c|} \hline element \#1 & element \#2 & \begin{tabular}{c} Forms ionic \\ compound? \end{tabular} & \begin{tabular}{c} empirical formula of \\ ionic compound \end{tabular} \\ \hline bromine & lithium & yes & & $\square$ \\ \hline oxygen & iodine & yes & & $\square$ \\ \hline cesium & sulfur & yes & no & $\square$ \\ \hline fluorine & calcium & yes & no & $\square$ \\ \hline \end{tabular}
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Solution

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Solution Steps

Step 1: Determine if the elements form an ionic compound

To determine if a pair of elements will form an ionic compound, we need to check if one element is a metal and the other is a non-metal. Ionic compounds typically form between metals and non-metals due to the transfer of electrons from the metal to the non-metal.

Step 2: Identify the empirical formula of the ionic compound

If the pair forms an ionic compound, we need to determine the empirical formula. The empirical formula is the simplest whole-number ratio of ions in the compound. This can be determined by balancing the charges of the ions.

Step 3: Analyze each pair of elements

  1. Bromine (Br) and Lithium (Li):

    • Bromine is a non-metal, and lithium is a metal.
    • They form an ionic compound.
    • Lithium has a charge of \(+1\) and bromine has a charge of \(-1\).
    • The empirical formula is \( \text{LiBr} \).

  2. Oxygen (O) and Iodine (I):

    • Both oxygen and iodine are non-metals.
    • They do not form an ionic compound.

  3. Cesium (Cs) and Sulfur (S):

    • Cesium is a metal, and sulfur is a non-metal.
    • They form an ionic compound.
    • Cesium has a charge of \(+1\) and sulfur has a charge of \(-2\).
    • The empirical formula is \( \text{Cs}_2\text{S} \).

Final Answer

\[ \begin{array}{|c|c|c|c|} \hline \text{Element \#1} & \text{Element \#2} & \text{Forms ionic compound?} & \text{Empirical formula of ionic compound} \\ \hline \text{Bromine} & \text{Lithium} & \text{Yes} & \boxed{\text{LiBr}} \\ \hline \text{Oxygen} & \text{Iodine} & \text{No} & \boxed{\text{N/A}} \\ \hline \text{Cesium} & \text{Sulfur} & \text{Yes} & \boxed{\text{Cs}_2\text{S}} \\ \hline \end{array} \]

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