Solve the equation \( 3x^{2} - 48 = 0 \) by taking square roots.
Isolate the \( x^{2} \) term.
Add 48 to both sides of the equation: \[ 3x^{2} - 48 + 48 = 0 + 48 \] Simplify: \[ 3x^{2} = 48 \]
Solve for \( x^{2} \).
Divide both sides by 3: \[ x^{2} = \frac{48}{3} \] Simplify: \[ x^{2} = 16 \]
Take the square root of both sides.
Take the square root of both sides: \[ x = \pm \sqrt{16} \] Simplify: \[ x = \pm 4 \]
\\(\boxed{x = \pm 4}\\)
The solution to the equation \( 3x^{2} - 48 = 0 \) is \\(\boxed{x = \pm 4}\\). The answer is a.
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