Questions: Solve the following radical equation. Enter your answer as an integer. If there is no solution indicate "No Solution".
sqrt(5y-1) = sqrt(2y+2)
y =
No Solution
Transcript text: Solve the following radical equation. Enter your answer as an integer. If there is no solution indicate "No Solution".
\[
\sqrt{5 y-1}=\sqrt{2 y+2}
\]
\[
y=\square
\]
No Solution
Solution
Solution Steps
Step 1: Square both sides of the equation
To eliminate the square roots, square both sides of the equation:
\[
(\sqrt{5y - 1})^2 = (\sqrt{2y + 2})^2
\]
This simplifies to:
\[
5y - 1 = 2y + 2
\]
Step 2: Solve for \( y \)
Subtract \( 2y \) from both sides to isolate the variable:
\[
5y - 2y - 1 = 2
\]
Simplify:
\[
3y - 1 = 2
\]
Step 3: Isolate \( y \)
Add 1 to both sides:
\[
3y = 3
\]
Divide both sides by 3:
\[
y = 1
\]
Step 4: Verify the solution
Substitute \( y = 1 \) back into the original equation to ensure it is valid:
\[
\sqrt{5(1) - 1} = \sqrt{2(1) + 2}
\]
Simplify:
\[
\sqrt{4} = \sqrt{4}
\]
Since both sides are equal, \( y = 1 \) is the correct solution.