Questions: Solve the following radical equation. Enter your answer as an integer. If there is no solution indicate "No Solution". sqrt(5y-1) = sqrt(2y+2) y = No Solution

Solve the following radical equation. Enter your answer as an integer. If there is no solution indicate "No Solution".

sqrt(5y-1) = sqrt(2y+2)

y = 

No Solution
Transcript text: Solve the following radical equation. Enter your answer as an integer. If there is no solution indicate "No Solution". \[ \sqrt{5 y-1}=\sqrt{2 y+2} \] \[ y=\square \] No Solution
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Solution

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Solution Steps

Step 1: Square both sides of the equation

To eliminate the square roots, square both sides of the equation: \[ (\sqrt{5y - 1})^2 = (\sqrt{2y + 2})^2 \] This simplifies to: \[ 5y - 1 = 2y + 2 \]

Step 2: Solve for \( y \)

Subtract \( 2y \) from both sides to isolate the variable: \[ 5y - 2y - 1 = 2 \] Simplify: \[ 3y - 1 = 2 \]

Step 3: Isolate \( y \)

Add 1 to both sides: \[ 3y = 3 \] Divide both sides by 3: \[ y = 1 \]

Step 4: Verify the solution

Substitute \( y = 1 \) back into the original equation to ensure it is valid: \[ \sqrt{5(1) - 1} = \sqrt{2(1) + 2} \] Simplify: \[ \sqrt{4} = \sqrt{4} \] Since both sides are equal, \( y = 1 \) is the correct solution.

\[ y = 1 \]

Final Answer

\(\boxed{y = 1}\)

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