Questions: Solve the following radical equation. Enter your answer as an integer. If there is no solution indicate "No Solution". sqrt(5y-1) = sqrt(2y+2) y = No Solution

Solve the following radical equation. Enter your answer as an integer. If there is no solution indicate "No Solution".

sqrt(5y-1) = sqrt(2y+2)

y = 

No Solution
Transcript text: Solve the following radical equation. Enter your answer as an integer. If there is no solution indicate "No Solution". \[ \sqrt{5 y-1}=\sqrt{2 y+2} \] \[ y=\square \] No Solution
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Solution

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Solution Steps

Step 1: Square both sides of the equation

To eliminate the square roots, square both sides of the equation: (5y1)2=(2y+2)2 (\sqrt{5y - 1})^2 = (\sqrt{2y + 2})^2 This simplifies to: 5y1=2y+2 5y - 1 = 2y + 2

Step 2: Solve for y y

Subtract 2y 2y from both sides to isolate the variable: 5y2y1=2 5y - 2y - 1 = 2 Simplify: 3y1=2 3y - 1 = 2

Step 3: Isolate y y

Add 1 to both sides: 3y=3 3y = 3 Divide both sides by 3: y=1 y = 1

Step 4: Verify the solution

Substitute y=1 y = 1 back into the original equation to ensure it is valid: 5(1)1=2(1)+2 \sqrt{5(1) - 1} = \sqrt{2(1) + 2} Simplify: 4=4 \sqrt{4} = \sqrt{4} Since both sides are equal, y=1 y = 1 is the correct solution.

y=1 y = 1

Final Answer

y=1\boxed{y = 1}

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