Questions: System A
Line 1: y=1/2 x+5/2
Line 2: y=-x-2
This system of equations is:
inconsistent
consistent dependent
consistent independent
This means the system has:
a unique solution
Solution: ,
infinitely many solutions
no solution
System B
Line 1: y=1/4 x+3
Line 2: -x+4 y=12
This system of equations is:
inconsistent
consistent dependent
consistent independent
This means the system has:
a unique solution
Solution: .
infinitely many solutions
no solution
System C
Line 1: y=-1/2 x
Line 2: y=-1/2 x+2
This system of equations is:
inconsistent
consistent dependent
consistent independent
This means the system has:
a unique solution
Solution: .
infinitely many solutions
no solution
Transcript text: System A
Line 1: $y=\frac{1}{2} x+\frac{5}{2}$
Line 2: $y=-x-2$
This system of equations is:
inconsistent
consistent dependent
consistent independent
This means the system has:
a unique solution
Solution: $\square$ ,
infinitely many solutions
no solution
System B
Line 1: $y=\frac{1}{4} x+3$
Line 2: $-x+4 y=12$
This system of equations is:
inconsistent
consistent dependent
consistent independent
This means the system has:
a unique solution
Solution: $\square$ . $\square$
infinitely many solutions
no solution
System C
Line 1: $y=-\frac{1}{2} x$
Line 2: $y=-\frac{1}{2} x+2$
This system of equations is:
inconsistent
consistent dependent
consistent independent
This means the system has:
a unique solution
Solution: $\square$ .])
infinitely many solutions
no solution
Solution
Solution Steps
Step 1: Analyze System A
The two lines in System A intersect at a single point (-2, 0).
Step 2: Analyze System B
Manipulating the second equation of System B, we have:
-x + 4y = 12
4y = x + 12
y = (1/4)x + 3
This is the same as the first equation, so the lines are coincident.
Step 3: Analyze System C
The two lines in System C are parallel, having the same slope (-1/2) but different intercepts.
Final Answer
System A: consistent independent, a unique solution (-2,0)
System B: consistent dependent, infinitely many solutions