To solve the given problems, we need to find transition matrices between different bases for the vector space \(\mathbb{P}_{2}\). The transition matrix from one basis to another can be found by expressing each vector of the first basis in terms of the second basis. For the coordinates of a polynomial in a given basis, we express the polynomial as a linear combination of the basis vectors.
a. To find the transition matrix from \(\mathcal{C}\) to the standard basis \(\mathcal{E}\), express each vector in \(\mathcal{C}\) in terms of \(\mathcal{E}\).
b. Similarly, express each vector in \(\mathcal{B}\) in terms of \(\mathcal{E}\) to find the transition matrix from \(\mathcal{B}\) to \(\mathcal{E}\).
c. The transition matrix from \(\mathcal{E}\) to \(\mathcal{B}\) is the inverse of the matrix found in part b.
To find the transition matrix from the basis \(\mathcal{C} = \{3x - 1, 3 + 3x\}\) to the standard basis \(\mathcal{E} = \{1, x\}\), we express each vector in \(\mathcal{C}\) in terms of \(\mathcal{E}\). The matrix \(\mathcal{C}\) is given by:
\[
C = \begin{bmatrix} -1 & 3 \\ 3 & 3 \end{bmatrix}
\]
The transition matrix \(T_{\mathcal{C}}^{\mathcal{E}}\) is the inverse of \(C\):
\[
T_{\mathcal{C}}^{\mathcal{E}} = \begin{bmatrix} -0.25 & 0.25 \\ 0.25 & 0.0833 \end{bmatrix}
\]
For the basis \(\mathcal{B} = \{1 + 2x, 2 + 5x\}\), we express each vector in \(\mathcal{B}\) in terms of \(\mathcal{E}\). The matrix \(\mathcal{B}\) is given by:
\[
B = \begin{bmatrix} 1 & 2 \\ 2 & 5 \end{bmatrix}
\]
The transition matrix \(T_{\mathcal{B}}^{\mathcal{E}}\) is the inverse of \(B\):
\[
T_{\mathcal{B}}^{\mathcal{E}} = \begin{bmatrix} 5 & -2 \\ -2 & 1 \end{bmatrix}
\]
The transition matrix from \(\mathcal{E}\) to \(\mathcal{B}\) is the inverse of \(T_{\mathcal{B}}^{\mathcal{E}}\):
\[
T_{\mathcal{E}}^{\mathcal{B}} = \begin{bmatrix} 1 & 2 \\ 2 & 5 \end{bmatrix}
\]
\[
T_{\mathcal{C}}^{\mathcal{E}} = \begin{bmatrix} -\frac{1}{4} & \frac{1}{4} \\ \frac{1}{4} & \frac{1}{12} \end{bmatrix}
\]