Questions: WeBWorK / MAT 1193 Fall 2024 / Homework 8 Antiderivatives Previous Problem Problem List Next Problem Homework 8 Antiderivatives: (1 point) Antiderivatives Find all possible functions with the given derivative. 1. If y′ = -1/x^2, then y= 2. If y′ = 1 - 1/x^2, then y= 3. If y′ = 6 + 1/x^2, then y= For additional help with this problem type, access the following resources: - Read Chapter 5.2 of the text.

WeBWorK / MAT 1193 Fall 2024 / Homework 8 Antiderivatives Previous Problem Problem List Next Problem

Homework 8 Antiderivatives: (1 point)

Antiderivatives

Find all possible functions with the given derivative. 1. If y′ = -1/x^2, then y= 2. If y′ = 1 - 1/x^2, then y= 3. If y′ = 6 + 1/x^2, then y=

For additional help with this problem type, access the following resources: - Read Chapter 5.2 of the text.
Transcript text: WeBWorK / MAT 1193 Fall 2024 / Homework 8 Antiderivatives Previous Problem Problem List Next Problem Homework 8 Antiderivatives: (1 point) Antiderivatives Find all possible functions with the given derivative. 1. If $y^{\prime}=\frac{-1}{x^{2}}$, then $y=$ $\square$ 2. If $y^{\prime}=1-\frac{1}{x^{2}}$, then $y=$ $\square$ 3. If $y^{\prime}=6+\frac{1}{x^{2}}$, then $y=$ $\square$ For additional help with this problem type, access the following resou - TEXT Read Chapter 5.2 of the text. Search
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Solution

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Solution Steps

Solution Approach

To find the antiderivative of a function, we need to integrate the given derivative. The antiderivative will include a constant of integration, \( C \), since the derivative of a constant is zero. For each given derivative, we will perform the integration to find the corresponding function.

  1. Integrate \( y' = \frac{-1}{x^2} \) to find \( y \).
  2. Integrate \( y' = 1 - \frac{1}{x^2} \) to find \( y \).
  3. Integrate \( y' = 6 + \frac{1}{x^2} \) to find \( y \).
Step 1: Antiderivative of \( y' = \frac{-1}{x^2} \)

To find the antiderivative, we integrate: \[ y = \int \frac{-1}{x^2} \, dx = C_1 + \frac{1}{x} \]

Step 2: Antiderivative of \( y' = 1 - \frac{1}{x^2} \)

Next, we integrate: \[ y = \int \left(1 - \frac{1}{x^2}\right) \, dx = C_2 + x + \frac{1}{x} \]

Step 3: Antiderivative of \( y' = 6 + \frac{1}{x^2} \)

Finally, we integrate: \[ y = \int \left(6 + \frac{1}{x^2}\right) \, dx = C_3 + 6x - \frac{1}{x} \]

Final Answer

The solutions for the antiderivatives are:

  1. \( y = C_1 + \frac{1}{x} \)
  2. \( y = C_2 + x + \frac{1}{x} \)
  3. \( y = C_3 + 6x - \frac{1}{x} \)

Thus, the final answers are: \[ \boxed{y = C_1 + \frac{1}{x}, \quad y = C_2 + x + \frac{1}{x}, \quad y = C_3 + 6x - \frac{1}{x}} \]

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