To determine if the high school students have unusually high math SAT scores, we first calculate the Z-score using the formula:
\[
z = \frac{X - \mu}{\sigma}
\]
where:
- \(X = 561\) (sample mean),
- \(\mu = 514\) (population mean),
- \(\sigma = \frac{111}{\sqrt{45}} \approx 16.5469\) (standard error).
Calculating the Z-score:
\[
z = \frac{561 - 514}{16.5469} \approx 2.84
\]
The standard error \(SE\) is calculated as follows:
\[
SE = \frac{\sigma}{\sqrt{n}} = \frac{111}{\sqrt{45}} \approx 16.55
\]
Next, we calculate the Z-test statistic:
\[
Z_{\text{test}} = \frac{\bar{x} - \mu_0}{SE} = \frac{561 - 514}{16.55} \approx 2.84
\]
For a right-tailed test, we find the p-value:
\[
P = 1 - T(z) \approx 0.0
\]
Since the p-value \(0.0\) is less than the significance level \(\alpha = 0.05\), we reject the null hypothesis. Thus, we conclude:
Yes, because the Z-score is not within the range of a usual event, namely within 95% mean of the sample means.