Questions: molecule or polyatomic ion polar or nonpolar? atom closest to negative side F2 polar nonpolar CS2 polar nonpolar CH3F polar nonpolar

molecule or polyatomic ion
polar or nonpolar?
atom closest to negative side
F2 
polar 
nonpolar

CS2
polar 
nonpolar

CH3F
polar 
nonpolar
Transcript text: molecule or olyatomic ion polar or nonpolar? atom closest to negative side $\mathrm{F}_{2}$ polar nonpolar $\square$ $\mathrm{CS}_{2}$ polar nonpolar $\square$ $\mathrm{CH}_{3} \mathrm{~F}$ polar nonpolar $\square$
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Solution

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Solution Steps

Step 1: Determine the Polarity of Each Molecule
  1. F\(_2\): This molecule consists of two identical fluorine atoms. Since the electronegativity difference between the atoms is zero, the molecule is nonpolar.

  2. CS\(_2\): Carbon disulfide is a linear molecule with two sulfur atoms symmetrically bonded to a central carbon atom. The electronegativity difference between carbon and sulfur is small, and the linear geometry results in the dipoles canceling each other out, making the molecule nonpolar.

  3. CH\(_3\)F: This molecule consists of a carbon atom bonded to three hydrogen atoms and one fluorine atom. The C-F bond is polar due to the significant electronegativity difference between carbon and fluorine. The molecule is not symmetrical, so the dipoles do not cancel out, making it polar.

Step 2: Identify the Atom Closest to the Negative Side
  1. F\(_2\): Since the molecule is nonpolar, there is no atom closer to the negative side.

  2. CS\(_2\): The molecule is nonpolar, so there is no atom closer to the negative side.

  3. CH\(_3\)F: The fluorine atom is the most electronegative and is closest to the negative side of the molecule.

Final Answer

\[ \begin{array}{c|l|c} \hline \text{molecule or} & \text{polar or} & \text{atom closest to} \\ \text{polyatomic ion} & \text{nonpolar?} & \text{negative side} \\ \hline \mathrm{F}_{2} & \text{nonpolar} & \boxed{\text{None}} \\ \hline \mathrm{CS}_{2} & \text{nonpolar} & \boxed{\text{None}} \\ \hline \mathrm{CH}_{3} \mathrm{~F} & \text{polar} & \boxed{\mathrm{F}} \\ \hline \end{array} \]

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