Questions: Write a balanced half-reaction for the reduction of bismuth oxide ion (BiO3-) to bismuth ion (Bi3+) in basic aqueous solution. Be sure to add physical state symbols where appropriate.
Transcript text: Write a balanced half-reaction for the reduction of bismuth oxide ion $\left(\mathrm{BiO}_{3}^{-}\right)$to bismuth ion $\left(\mathrm{Bi}^{3+}\right)$ in basic aqueous solution. Be sure to add physical state symbols where appropriate.
Solution
Solution Steps
Step 1: Identify the Oxidation States
First, identify the oxidation states of bismuth in the reactant and product. In \(\mathrm{BiO}_3^-\), bismuth is in the +5 oxidation state, and in \(\mathrm{Bi}^{3+}\), it is in the +3 oxidation state.
Step 2: Write the Unbalanced Half-Reaction
Write the unbalanced half-reaction for the reduction process:
\[
\mathrm{BiO}_3^- (aq) \rightarrow \mathrm{Bi}^{3+} (aq)
\]
Step 3: Balance the Atoms Other Than Oxygen and Hydrogen
In this case, bismuth is already balanced with one atom on each side.
Step 4: Balance the Oxygen Atoms
Add water molecules to balance the oxygen atoms. There are three oxygen atoms on the left, so add three water molecules to the right:
\[
\mathrm{BiO}_3^- (aq) \rightarrow \mathrm{Bi}^{3+} (aq) + 3\mathrm{H}_2\mathrm{O} (l)
\]
Step 5: Balance the Hydrogen Atoms
Add hydroxide ions (\(\mathrm{OH}^-\)) to balance the hydrogen atoms. There are six hydrogen atoms on the right, so add six hydroxide ions to the left:
\[
\mathrm{BiO}_3^- (aq) + 6\mathrm{OH}^- (aq) \rightarrow \mathrm{Bi}^{3+} (aq) + 3\mathrm{H}_2\mathrm{O} (l)
\]
Step 6: Balance the Charge
Balance the charge by adding electrons. The left side has a charge of \(-7\) (one \(\mathrm{BiO}_3^-\) and six \(\mathrm{OH}^-\)), and the right side has a charge of \(+3\). Add 10 electrons to the left side to balance the charge:
\[
\mathrm{BiO}_3^- (aq) + 6\mathrm{OH}^- (aq) + 10e^- \rightarrow \mathrm{Bi}^{3+} (aq) + 3\mathrm{H}_2\mathrm{O} (l)
\]
Final Answer
The balanced half-reaction for the reduction of bismuth oxide ion to bismuth ion in basic aqueous solution is:
\[
\boxed{\mathrm{BiO}_3^- (aq) + 6\mathrm{OH}^- (aq) + 10e^- \rightarrow \mathrm{Bi}^{3+} (aq) + 3\mathrm{H}_2\mathrm{O} (l)}
\]