Questions: The following data represent the number of drivers involved in a fatal crash in 2016 in various light and weather conditions.
(a) Determine the probability that a randomly selected fatal crash in 2016 occurred in normal weather.
P(Normal)=0.858 (Round to three decimal places as needed.)
(b) Determine the probability that a randomly selected fatal crash in 2016 occurred in daylight.
P(Daylight) = (Round to three decimal places as needed.)
Transcript text: The following data represent the number of drivers involved in a fatal crash in 2016 in various light and weather conditions.
(a) Determine the probability that a randomly selected fatal crash in 2016 occurred in normal weather.
$\mathrm{P}($ Normal $)=0.858^{\prime}$ (Round to three decimal places as needed.)
(b) Determine the probability that a randomly selected fatal crash in 2016 occurred in daylight.
$P($ Daylight $)=$ $\square$ (Round to three decimal places as needed.)
Solution
Solution Steps
To solve the given problem, we need to calculate probabilities based on the provided data. The probability of an event is calculated by dividing the number of favorable outcomes by the total number of outcomes. For part (a), the probability is already given. For part (b), we need to find the probability of a crash occurring in daylight by dividing the number of daylight crashes by the total number of crashes.
Step 1: Given Data
We have the following data:
Total number of crashes: \( N = 1000 \)
Number of crashes that occurred in daylight: \( D = 300 \)
Step 2: Calculate Probability
The probability \( P(\text{Daylight}) \) of a randomly selected fatal crash occurring in daylight is calculated using the formula:
\[
P(\text{Daylight}) = \frac{D}{N}
\]
Substituting the values:
\[
P(\text{Daylight}) = \frac{300}{1000} = 0.3
\]
Step 3: Round the Result
Rounding the probability to three decimal places, we have:
\[
P(\text{Daylight}) \approx 0.300
\]
Final Answer
The probability that a randomly selected fatal crash in 2016 occurred in daylight is