The problem states that the perimeter of the triangle is 42, and the lengths of two sides are given as 6 and 8.
Since the triangle is a right triangle, we can use the Pythagorean theorem: \[ a^2 + b^2 = c^2 \] where \( a = 6 \) and \( b = 8 \).
\[ 6^2 + 8^2 = c^2 \] \[ 36 + 64 = c^2 \] \[ 100 = c^2 \] \[ c = \sqrt{100} \] \[ c = 10 \]
The perimeter is the sum of all sides: \[ 6 + 8 + 10 = 24 \]
There seems to be a discrepancy because the given perimeter is 42, but the calculated perimeter is 24. Therefore, the given information might be incorrect or incomplete.
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