Questions: Let the function f be defined as follows.
f(x) = 6 sqrt(x-3)
Answer the following. (a) For h != 0, find the difference quotient (f(x+h)-f(x)) / h.
Simplify your answer so that the resulting expression is defined at h=0.
(f(x+h)-f(x)) / h =
Transcript text: Let the function $f$ be defined as follows.
\[
f(x)=6 \sqrt{x-3}
\]
Answer the following.
(a) For $h \neq 0$, find the difference quotient $\frac{f(x+h)-f(x)}{h}$.
Simplify your answer so that the resulting expression is defined at $h=0$.
\[
\frac{f(x+h)-f(x)}{h}=
\]
Solution
Solution Steps
To find the difference quotient \(\frac{f(x+h)-f(x)}{h}\) for the function \(f(x) = 6 \sqrt{x-3}\), we need to:
Substitute \(f(x)\) and \(f(x+h)\) into the difference quotient formula.
Simplify the expression to make it defined at \(h=0\).
Step 1: Define the Function and Difference Quotient
Given the function \( f(x) = 6 \sqrt{x-3} \), we need to find the difference quotient:
\[
\frac{f(x+h) - f(x)}{h}
\]
Step 2: Substitute \( f(x) \) and \( f(x+h) \)
First, we substitute \( f(x) \) and \( f(x+h) \) into the difference quotient:
\[
f(x) = 6 \sqrt{x-3}
\]
\[
f(x+h) = 6 \sqrt{x+h-3}
\]
\[
\frac{f(x+h) - f(x)}{h} = \frac{6 \sqrt{x+h-3} - 6 \sqrt{x-3}}{h}
\]
Step 3: Simplify the Expression
We can factor out the common factor of 6 in the numerator:
\[
\frac{6 \sqrt{x+h-3} - 6 \sqrt{x-3}}{h} = 6 \cdot \frac{\sqrt{x+h-3} - \sqrt{x-3}}{h}
\]
Step 4: Rationalize the Numerator
To simplify further, we rationalize the numerator by multiplying and dividing by the conjugate:
\[
6 \cdot \frac{\sqrt{x+h-3} - \sqrt{x-3}}{h} \cdot \frac{\sqrt{x+h-3} + \sqrt{x-3}}{\sqrt{x+h-3} + \sqrt{x-3}}
\]
\[
= 6 \cdot \frac{(\sqrt{x+h-3})^2 - (\sqrt{x-3})^2}{h (\sqrt{x+h-3} + \sqrt{x-3})}
\]
\[
= 6 \cdot \frac{(x+h-3) - (x-3)}{h (\sqrt{x+h-3} + \sqrt{x-3})}
\]
\[
= 6 \cdot \frac{h}{h (\sqrt{x+h-3} + \sqrt{x-3})}
\]
\[
= 6 \cdot \frac{1}{\sqrt{x+h-3} + \sqrt{x-3}}
\]
Final Answer
The simplified difference quotient is:
\[
\boxed{6 \cdot \frac{1}{\sqrt{x+h-3} + \sqrt{x-3}}}
\]