Questions: Triangle Q T U is congruent to triangle R S U. Complete the proof that triangle Q R T is congruent to triangle R Q S.
1. Triangle Q T U is congruent to triangle R S U - Given
2. Line segment Q T is congruent to line segment R S
3. Line segment Q U is congruent to line segment R U - CPCTC
4. Line segment S U is congruent to line segment T U
5. Angle Q T U is congruent to angle R S U - CPCTC
6. Q S equals Q U plus S U - Additive Property of Length
7. R T equals R U plus T U - Additive Property of Length
8. Q S equals R U plus T U - Substitution
9. Q S equals R T - Transitive Property of Equality
10. Triangle Q R T is congruent to triangle R Q S
Transcript text: $\triangle Q T U \cong \triangle R S U$. Complete the proof that $\triangle Q R T \cong \triangle R Q S$.
\begin{tabular}{|l|l|l}
\hline & Statement & Reason \\
\hline 1 & $\triangle Q T U \cong \triangle R S U$ & Given \\
\hline 2 & $\overline{Q T} \cong \overline{R S}$ & \\
3 & $\overline{Q U} \cong \overline{R U}$ & CPCTC \\
4 & $\overline{S U} \cong \overline{T U}$ & \\
5 & $\angle Q T U \cong \angle R S U$ & CPCTC \\
6 & $Q S=Q U+S U$ & Additive Property of Length \\
7 & $R T=R U+T U$ & Additive Property of Length \\
8 & $Q S=R U+T U$ & Substitution \\
9 & $Q S=R T$ & Transitive Property of Equality \\
10 & $\Delta Q R T \cong \triangle R Q S$ & \\
\hline
\end{tabular}
Solution
Solution Steps
Step 1: Given
The problem states that \( \triangle QTU \cong \triangle RSU \).
Step 2: Corresponding Sides
Since \( \triangle QTU \cong \triangle RSU \), the corresponding sides are congruent:
\[ \overline{QT} \cong \overline{RS} \]
Step 3: Corresponding Parts of Congruent Triangles are Congruent (CPCTC)
From the congruence of the triangles, the corresponding parts are congruent:
\[ \overline{QU} \cong \overline{RU} \]
Step 4: Corresponding Parts of Congruent Triangles are Congruent (CPCTC)
Similarly, the other corresponding parts are congruent:
\[ \overline{SU} \cong \overline{TU} \]
Step 5: Corresponding Angles
The corresponding angles of the congruent triangles are also congruent:
\[ \angle QTU \cong \angle RSU \]
Step 6: Additive Property of Length
The length of \( \overline{QS} \) can be expressed as the sum of the lengths of \( \overline{QU} \) and \( \overline{SU} \):
\[ QS = QU + SU \]
Step 7: Additive Property of Length
Similarly, the length of \( \overline{RT} \) can be expressed as the sum of the lengths of \( \overline{RU} \) and \( \overline{TU} \):
\[ RT = RU + TU \]
Step 8: Substitution
Since \( \overline{QU} \cong \overline{RU} \) and \( \overline{SU} \cong \overline{TU} \), we can substitute these into the previous equations:
\[ QS = RU + TU \]
Step 9: Transitive Property of Equality
From the previous steps, we have:
\[ QS = RT \]
Step 10: Conclusion
Since \( \overline{QT} \cong \overline{RS} \), \( \overline{QS} \cong \overline{RT} \), and \( \angle QTU \cong \angle RSU \), by the definition of congruent triangles, we have:
\[ \triangle QRT \cong \triangle RQS \]