To find the limits in this problem, we need to compute the partial derivatives of the function \( f(x, y) = \sqrt{y}(y+7) \) with respect to \( x \) and \( y \). For part (a), since the function does not explicitly depend on \( x \), the partial derivative with respect to \( x \) will be zero. For part (b), we will compute the partial derivative with respect to \( y \) using the limit definition of a derivative.
Step 1: Function Definition
We start with the function defined as:
\[
f(x, y) = \sqrt{y}(y + 7)
\]
Step 2: Partial Derivative with Respect to \( x \)
To find the limit for part (a):
\[
\lim_{\Delta x \rightarrow 0} \frac{f(x+\Delta x, y) - f(x, y)}{\Delta x}
\]
Since \( f \) does not depend on \( x \), we have:
\[
\frac{\partial f}{\partial x} = 0
\]
Step 3: Partial Derivative with Respect to \( y \)
For part (b), we compute the limit:
\[
\lim_{\Delta y \rightarrow 0} \frac{f(x, y+\Delta y) - f(x, y)}{\Delta y}
\]
Substituting \( f(y + \Delta y) \):
\[
f(y + \Delta y) = \sqrt{y + \Delta y} \left( (y + \Delta y) + 7 \right)
\]
The partial derivative with respect to \( y \) is given by:
\[
\frac{\partial f}{\partial y} = \frac{3y}{2\sqrt{y}} + \frac{7}{2\sqrt{y}}
\]
This simplifies to:
\[
\frac{\partial f}{\partial y} = \frac{3y + 7}{2\sqrt{y}}
\]
Final Answer
Thus, the answers to the limits are:
For part (a): \( \boxed{0} \)
For part (b): \( \boxed{\frac{3y + 7}{2\sqrt{y}}} \)