Questions: A single cylinder of a nine-cylinder engine contains at total volume of 186 cu .in. with the piston at bottom dead center. If the engine has a compression ratio of 6:1, what is the total engine displacement? 2,395 in^3 1,395 in^3 1,395 in^2

Solution Steps

We are given a single cylinder volume of 186 cubic inches at bottom dead center and a compression ratio of 6:1. We need to find the total engine displacement for a nine-cylinder engine.

The compression ratio is defined as the ratio of the total volume (with the piston at bottom dead center) to the compressed volume (with the piston at top dead center).

Given:

• Total volume at bottom dead center, \( V_{BDC} = 186 \, \text{cu in} \)
• Compression ratio, \( CR = 6:1 \)

The compressed volume \( V_{TDC} \) can be calculated as: \[ CR = \frac{V_{BDC}}{V_{TDC}} \implies V_{TDC} = \frac{V_{BDC}}{CR} = \frac{186}{6} = 31 \, \text{cu in} \]

The displacement volume of one cylinder is: \[ V_{displacement} = V_{BDC} - V_{TDC} = 186 - 31 = 155 \, \text{cu in} \]

Since the engine has nine cylinders, the total engine displacement is: \[ \text{Total displacement} = 9 \times V_{displacement} = 9 \times 155 = 1395 \, \text{cu in} \]

Final Answer