Questions: Find the length of the arc, s, on a circle of radius r intercepted by a central angle θ. Express the arc length in terms of π. Then round your answer to two decimal places.
Radius, r=12 inches; Central angle, θ=55°
s= inches
(Simplify your answer. Type an exact answer in terms of π. Use integers or fractions for any numbers in the expression.)
s= inches
(Round to two decimal places as needed.)
Transcript text: Find the length of the arc, $s$, on a circle of radius $r$ intercepted by a central angle $\theta$. Express the arc length in terms of $\pi$. Then round your answer to two decimal places.
Radius, $r=12$ inches; Central angle, $\theta=55^{\circ}$
$s=$ $\square$ inches
(Simplify your answer. Type an exact answer in terms of $\pi$. Use integers or fractions for any numbers in the expression.)
$s=$ $\square$ inches
(Round to two decimal places as needed.)
Solution
Solution Steps
To find the length of the arc, $s$, on a circle of radius $r$ intercepted by a central angle $\theta$, we can use the formula:
\[ s = r \theta \]
where $\theta$ is in radians. First, we need to convert the angle from degrees to radians using the conversion factor:
\[ \theta_{\text{radians}} = \theta_{\text{degrees}} \times \frac{\pi}{180} \]
Then, we can calculate the arc length in terms of $\pi$ and also round it to two decimal places.
Step 1: Convert Degrees to Radians
To find the arc length, we first convert the central angle from degrees to radians using the formula:
\[
\theta_{\text{radians}} = \theta_{\text{degrees}} \times \frac{\pi}{180}
\]
Substituting the given value:
\[
\theta_{\text{radians}} = 55 \times \frac{\pi}{180} \approx 0.9599
\]
Step 2: Calculate the Arc Length
Next, we use the formula for arc length:
\[
s = r \theta
\]
Substituting the values of \( r = 12 \) inches and \( \theta \approx 0.9599 \):
\[
s \approx 12 \times 0.9599 \approx 11.5192
\]
Step 3: Round the Arc Length
Finally, we round the arc length to two decimal places:
\[
s \approx 11.52
\]
Final Answer
The exact arc length in terms of \(\pi\) is approximately \(11.5192\) inches, and rounded to two decimal places, it is \(\boxed{s = 11.52}\).