Questions: Add the appropriate coefficient to balance the following chemical equations. 16. Cu(NO3)2(aq) + NaOH(aq) -> Cu(OH)2(s) + NaNO3(aq) 17. H3PO4(aq) + KOH(aq) -> H2O(l) + K3PO4(aq)

Add the appropriate coefficient to balance the following chemical equations.
16. Cu(NO3)2(aq) + NaOH(aq) -> Cu(OH)2(s) + NaNO3(aq)
17. H3PO4(aq) + KOH(aq) -> H2O(l) + K3PO4(aq)

Transcript text: Add the appropriate coefficient to balance the following chemical equations. 16. $\mathrm{Cu}\left(\mathrm{NO}_{3}\right)_{2}(\mathrm{aq})+$ $\qquad$ $\mathrm{NaOH}(\mathrm{aq}) \rightarrow \mathrm{Cu}(\mathrm{OH})_{2}(\mathrm{~s})+$ $\qquad$ $\mathrm{NaNO}_{3}(\mathrm{aq})$ 17. $\mathrm{H}_{3} \mathrm{PO}_{4}(\mathrm{aq})+$ $\qquad$ $\mathrm{KOH}(\mathrm{aq}) \rightarrow$ $\qquad$ $\mathrm{H}_{2} \mathrm{O}(\mathrm{l})+\mathrm{K}_{3} \mathrm{PO}_{4}(\mathrm{aq})$

Solution

Solution Steps

Step 1: Identify the Compounds and Their Formulas

For equation 16:
- Reactants: $\mathrm{Cu}\left(\mathrm{NO}_{3}\right)_{2}$ and $\mathrm{NaOH}$
- Products: $\mathrm{Cu}(\mathrm{OH})_{2}$ and $\mathrm{NaNO}_{3}$
For equation 17:
- Reactants: $\mathrm{H}_{3} \mathrm{PO}_{4}$ and $\mathrm{KOH}$
- Products: $\mathrm{H}_{2} \mathrm{O}$ and $\mathrm{K}_{3} \mathrm{PO}_{4}$

Step 2: Balance the First Equation

Balance copper ($\mathrm{Cu}$): 1 $\mathrm{Cu}$ on both sides.
Balance nitrate ($\mathrm{NO}_{3}$): 2 $\mathrm{NO}_{3}$ on the left, so 2 $\mathrm{NaNO}_{3}$ on the right.
Balance sodium ($\mathrm{Na}$): 2 $\mathrm{Na}$ on the right, so 2 $\mathrm{NaOH}$ on the left.
Balance hydroxide ($\mathrm{OH}$): 2 $\mathrm{OH}$ on both sides.

Step 3: Balance the Second Equation

Balance potassium ($\mathrm{K}$): 3 $\mathrm{K}$ in $\mathrm{K}_{3} \mathrm{PO}_{4}$, so 3 $\mathrm{KOH}$ on the left.
Balance phosphate ($\mathrm{PO}_{4}$): 1 $\mathrm{PO}_{4}$ on both sides.
Balance hydrogen ($\mathrm{H}$): 3 $\mathrm{H}$ from $\mathrm{H}_{3} \mathrm{PO}_{4}$ and 3 $\mathrm{H}$ from 3 $\mathrm{KOH}$, making 6 $\mathrm{H}$ total, so 3 $\mathrm{H}_{2} \mathrm{O}$ on the right.

Final Answer

For equation 16: $ \boxed{2} $
For equation 17: $ \boxed{3} $

Was this solution helpful?

Unhelpful

Helpful

Questions asked by other users

Next >

Thank you for your feedback.

Copied!