Questions: A map has a scale of 1''=50, how long is a property line on the map if the distance in the field measured to be 532.5'?
11.65 inches
10.56 inches
10.65 feet
10.65 inches
Transcript text: A map has a scale of $1^{\prime \prime}=50$, how long is a property line on the map if the distance in the field measured to be 532.5'?
11.65 inches
10.56 inches
10.65 feet
10.65 inches
Solution
Solution Steps
To solve the problem, we need to convert the real-world distance to the map distance using the given scale. The scale is $1^{\prime \prime} = 50'$, which means 1 inch on the map represents 50 feet in the real world. We will divide the real-world distance by the scale factor to find the map distance in inches.
Solution Approach
Identify the real-world distance (532.5 feet).
Identify the scale (1 inch = 50 feet).
Divide the real-world distance by the scale factor to get the map distance in inches.
Step 1: Identify the Given Values
We are given the real-world distance of the property line as \( 532.5 \) feet and the scale of the map as \( 1^{\prime \prime} = 50 \) feet.
Step 2: Set Up the Calculation
To find the length of the property line on the map in inches, we use the formula:
\[
\text{Map Distance (inches)} = \frac{\text{Real World Distance (feet)}}{\text{Scale Factor (feet per inch)}}
\]
Substituting the known values:
\[
\text{Map Distance} = \frac{532.5 \text{ feet}}{50 \text{ feet/inch}}
\]