Questions: The given equation is either linear or equivalent to a linear equation.
4/(x+1)+1/(x^2-1)=5/(x-1)
Transcript text: The given equation is either linear or equivalent to a linear equation.
\[
\frac{4}{x+1}+\frac{1}{x^{2}-1}=\frac{5}{x-1}
\]
Solution
Solution Steps
To solve the given equation, we first recognize that it involves rational expressions. The goal is to find a common denominator to combine the fractions on the left-hand side. Notice that \(x^2 - 1\) can be factored as \((x+1)(x-1)\). Thus, the common denominator for all terms is \((x+1)(x-1)\). Multiply each term by this common denominator to eliminate the fractions, then simplify and solve the resulting linear equation.
Step 1: Identify the Common Denominator
The given equation is:
\[
\frac{4}{x+1} + \frac{1}{x^2-1} = \frac{5}{x-1}
\]
Recognize that \(x^2 - 1\) can be factored as \((x+1)(x-1)\). Thus, the common denominator for all terms is \((x+1)(x-1)\).
Step 2: Eliminate the Fractions
Multiply each term by the common denominator \((x+1)(x-1)\) to eliminate the fractions:
\[
4(x-1) + 1 = 5(x+1)
\]
Step 3: Simplify and Solve the Equation
Simplify the equation:
\[
4x - 4 + 1 = 5x + 5
\]
Combine like terms:
\[
4x - 3 = 5x + 5
\]
Rearrange the equation to isolate \(x\):
\[
4x - 5x = 5 + 3
\]
\[
-x = 8
\]
Multiply both sides by \(-1\):
\[
x = -8
\]