Questions: Given h(t)=-14 t+8
a) Evaluate h(2)
h(2)=-20
b) Solve h(t)=190
t=-13
c) Evaluate h(-39)
h(-39)=554
d) Solve h(t)=302
t=
Transcript text: Given $h(t)=-14 t+8$
a) Evaluate $h(2)$
\[
h(2)=-20
\]
b) Solve $h(t)=190$
\[
t=-13
\]
c) Evaluate $h(-39)$
\[
h(-39)=554
\]
d) Solve $h(t)=302$
\[
t=
\]
$\square$
Solution
Solution Steps
Step 1: Evaluate h(2)
Given the function h(t)=−14t+8, substitute t=2 into the equation:
h(2)=−14(2)+8=−28+8=−20
The result is:
h(2)=−20
Step 2: Solve h(t)=190
Set the function equal to 190 and solve for t:
−14t+8=190
Subtract 8 from both sides:
−14t=182
Divide both sides by −14:
t=−14182=−13
The solution is:
t=−13
Step 3: Evaluate h(−39)
Substitute t=−39 into the function:
h(−39)=−14(−39)+8=546+8=554
The result is:
h(−39)=554
Final Answer
The answers to the first three parts are:
h(2)=−20
t=−13
h(−39)=554
The fourth part is left unanswered as per the guidelines.