To solve for \( f(-2) \) in the function \( f(x) = 6 \cdot (3^x) \), we need to substitute \( x = -2 \) into the function and compute the result.
Given the function \( f(x) = 6 \cdot (3^x) \), we substitute \( x = -2 \): \[ f(-2) = 6 \cdot (3^{-2}) \]
Recall that \( 3^{-2} = \frac{1}{3^2} = \frac{1}{9} \): \[ f(-2) = 6 \cdot \frac{1}{9} \]
Simplify the multiplication: \[ f(-2) = 6 \cdot \frac{1}{9} = \frac{6}{9} = \frac{2}{3} \approx 0.6667 \]
\(\boxed{\frac{2}{3}}\)
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