Questions: Let f(x)=(x^2-4x-21)/(x=7). Find a) limx -> 7 f(x) and b) limx -> 0 f(x).
a) Select the correct choice below and, if necessary, fill in the answer box to complete your choice.
A. limx -> 7 f(x)=□ (Simplify your answer.)
B. The limit does not exist.
b) Select the correct choice below and, if necessary, fill in the answer box to complete your choice.
A. limx -> 0 f(x)=□ (Simplify your answer.)
B. The limit does not exist.
Transcript text: Let $f(x)=\frac{x^{2}-4 x-21}{x=7}$. Find a) $\lim _{x \rightarrow 7} f(x)$ and b) $\lim _{x \rightarrow 0} f(x)$.
a) Select the correct choice below and, if necessary, fill in the answer box to complete your choice.
A. $\lim _{x \rightarrow 7} f(x)=\square$ (Simplify your answer.)
B. The limit does not exist.
b) Select the correct choice below and, if necessary, fill in the answer box to complete your choice.
A. $\lim _{x \rightarrow 0} f(x)=\square$ (Simplify your answer.)
B. The limit does not exist.
Solution
Solution Steps
Step 1: Evaluate \(\lim_{x \rightarrow 7} f(x)\)
To find \(\lim_{x \rightarrow 7} f(x)\), we first simplify the function \( f(x) = \frac{x^2 - 4x - 21}{x - 7} \). We factor the numerator:
Next, we find \(\lim_{x \rightarrow 0} f(x)\). Since we have already simplified \( f(x) \) to \( x + 3 \) for \( x \neq 7 \), we can directly substitute \( x = 0 \):