Questions: Counting significant digits when measurements are multiplied or divided Delena Multiply or divide the following measurements. Be sure each answer you enter contains the correct number of significant digits. - 784.14 g / 0.80 mL = □ g/mL - 93.4 mol/L * 53 L = □ mol - 704.66 m / 64.12 s = □ m/s

Counting significant digits when measurements are multiplied or divided

Delena

Multiply or divide the following measurements. Be sure each answer you enter contains the correct number of significant digits.

- 784.14 g / 0.80 mL = □ g/mL
- 93.4 mol/L * 53 L = □ mol
- 704.66 m / 64.12 s = □ m/s
Transcript text: Counting significant digits when measurements are multiplied or divided 0.5 Delena Multiply or divide the following measurements. Be sure each answer you enter contains the correct number of significant digits. \[ \begin{array}{l} 784.14 \mathrm{~g} \div 0.80 \mathrm{~mL}=\square \frac{\mathrm{g}}{\mathrm{~mL}} \\ 93.4 \frac{\mathrm{~mol}}{\mathrm{~L}} \times 53 . \mathrm{L}=\square \mathrm{mol} \\ 704.66 \mathrm{~m} \div 64.12 \mathrm{~s}=\square \frac{\mathrm{m}}{\mathrm{~s}} \end{array} \]
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Solution

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Solution Steps

Step 1: Determine the number of significant digits in each measurement
  1. For 784.14 g784.14 \mathrm{~g} and 0.80 mL0.80 \mathrm{~mL}:

    • 784.14 g784.14 \mathrm{~g} has 5 significant digits.
    • 0.80 mL0.80 \mathrm{~mL} has 2 significant digits.
  2. For 93.4 mol L93.4 \frac{\mathrm{~mol}}{\mathrm{~L}} and 53 L53 \mathrm{~L}:

    • 93.4 mol L93.4 \frac{\mathrm{~mol}}{\mathrm{~L}} has 3 significant digits.
    • 53 L53 \mathrm{~L} has 2 significant digits.
  3. For 704.66 m704.66 \mathrm{~m} and 64.12 s64.12 \mathrm{~s}:

    • 704.66 m704.66 \mathrm{~m} has 5 significant digits.
    • 64.12 s64.12 \mathrm{~s} has 4 significant digits.
Step 2: Perform the calculations
  1. 784.14 g÷0.80 mL784.14 \mathrm{~g} \div 0.80 \mathrm{~mL}: 784.14 g0.80 mL=980.175g mL \frac{784.14 \mathrm{~g}}{0.80 \mathrm{~mL}} = 980.175 \frac{\mathrm{g}}{\mathrm{~mL}}

  2. 93.4 mol L×53 L93.4 \frac{\mathrm{~mol}}{\mathrm{~L}} \times 53 \mathrm{~L}: 93.4 mol L×53 L=4950.2mol 93.4 \frac{\mathrm{~mol}}{\mathrm{~L}} \times 53 \mathrm{~L} = 4950.2 \mathrm{mol}

  3. 704.66 m÷64.12 s704.66 \mathrm{~m} \div 64.12 \mathrm{~s}: 704.66 m64.12 s=10.987m s \frac{704.66 \mathrm{~m}}{64.12 \mathrm{~s}} = 10.987 \frac{\mathrm{m}}{\mathrm{~s}}

Step 3: Round the results to the correct number of significant digits
  1. 784.14 g÷0.80 mL784.14 \mathrm{~g} \div 0.80 \mathrm{~mL}:

    • The result should have 2 significant digits (the smallest number of significant digits in the measurements). 980.175980g mL 980.175 \rightarrow 980 \frac{\mathrm{g}}{\mathrm{~mL}}
  2. 93.4 mol L×53 L93.4 \frac{\mathrm{~mol}}{\mathrm{~L}} \times 53 \mathrm{~L}:

    • The result should have 2 significant digits. 4950.25000mol 4950.2 \rightarrow 5000 \mathrm{mol}
  3. 704.66 m÷64.12 s704.66 \mathrm{~m} \div 64.12 \mathrm{~s}:

    • The result should have 4 significant digits. 10.98710.99m s 10.987 \rightarrow 10.99 \frac{\mathrm{m}}{\mathrm{~s}}

Final Answer

784.14 g÷0.80 mL=980g mL93.4 mol L×53 L=5000mol704.66 m÷64.12 s=10.99m s \begin{array}{l} 784.14 \mathrm{~g} \div 0.80 \mathrm{~mL} = \boxed{980 \frac{\mathrm{g}}{\mathrm{~mL}}} \\ 93.4 \frac{\mathrm{~mol}}{\mathrm{~L}} \times 53 \mathrm{~L} = \boxed{5000 \mathrm{mol}} \\ 704.66 \mathrm{~m} \div 64.12 \mathrm{~s} = \boxed{10.99 \frac{\mathrm{m}}{\mathrm{~s}}} \end{array}

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