Questions: A bacteria culture initially contains 2000 bacteria and doubles every half hour. Find the size of the bacterial population after 20 minutes. Find the size of the bacterial population after 7 hours.

A bacteria culture initially contains 2000 bacteria and doubles every half hour.
Find the size of the bacterial population after 20 minutes. 

Find the size of the bacterial population after 7 hours.
Transcript text: A bacteria culture initially contains 2000 bacteria and doubles every half hour. Find the size of the bacterial population after 20 minutes. Find the size of the bacterial population after 7 hours.
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Solution

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Solution Steps

Step 1: Calculate the number of doubling intervals

To find out how many times the population has doubled, we divide the future time (0.333) by the doubling interval (0.5). \[N = \frac{0.333}{0.5} = 0.667\]

Step 2: Calculate the future population size

Using the formula \(P = P0 \times 2^N\), where \(P0\) is the initial population size, and \(N\) is the number of doubling intervals, we find the future population size. Given \(P0 = 2000\) and \(N = 0.667\), \[P = 2000 \times 2^{0.667} = 3174.8\]

Final Answer: The size of the bacterial population after 0.333 units of time will be approximately 3174.8.

Step 1: Calculate the number of doubling intervals

To find out how many times the population has doubled, we divide the future time (7) by the doubling interval (0.5). \[N = \frac{7}{0.5} = 14\]

Step 2: Calculate the future population size

Using the formula \(P = P0 \times 2^N\), where \(P0\) is the initial population size, and \(N\) is the number of doubling intervals, we find the future population size. Given \(P0 = 2000\) and \(N = 14\), \[P = 2000 \times 2^{14} = 32768000\]

Final Answer: The size of the bacterial population after 7 units of time will be approximately 32768000.
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