Questions: Part A Which of the following solutions will not form a precipitate when added to 0.10 M NaOH ? 0.10 M FeCl2 0.10 M NH4Br 0.10 M MgBr2

Part A Which of the following solutions will not form a precipitate when added to 0.10 M NaOH ? 0.10 M FeCl2 0.10 M NH4Br 0.10 M MgBr2
Transcript text: Part A Which of the following solutions will not form a precipitate when added to 0.10 M NaOH ? $0.10 \mathrm{MFeCl}_{2}$ $0.10 \mathrm{M} \mathrm{NH}_{4} \mathrm{Br}$ $0.10 \mathrm{M} \mathrm{MgBr}_{2}$ Submit Request Answer Provide Feedback
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Solution

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Solution Steps

Step 1: Identify the possible reactions

When a solution is added to 0.10 M NaOH, we need to consider the possible reactions that could occur, specifically the formation of insoluble hydroxides. The relevant reactions are:

  1. \( \text{FeCl}_2 + 2\text{NaOH} \rightarrow \text{Fe(OH)}_2 \downarrow + 2\text{NaCl} \)
  2. \( \text{NH}_4\text{Br} + \text{NaOH} \rightarrow \text{NH}_3 \uparrow + \text{H}_2\text{O} + \text{NaBr} \)
  3. \( \text{MgBr}_2 + 2\text{NaOH} \rightarrow \text{Mg(OH)}_2 \downarrow + 2\text{NaBr} \)
Step 2: Determine solubility of products
  • Fe(OH)\(_2\): Iron(II) hydroxide is insoluble in water and will form a precipitate.
  • NH\(_3\): Ammonia is a gas and will not form a precipitate.
  • Mg(OH)\(_2\): Magnesium hydroxide is insoluble in water and will form a precipitate.
Step 3: Identify the solution that does not form a precipitate

From the reactions and solubility information, we see that:

  • \( \text{FeCl}_2 \) forms a precipitate of Fe(OH)\(_2\).
  • \( \text{NH}_4\text{Br} \) does not form a precipitate; instead, it releases ammonia gas.
  • \( \text{MgBr}_2 \) forms a precipitate of Mg(OH)\(_2\).

Final Answer

The solution that will not form a precipitate when added to 0.10 M NaOH is \( \boxed{0.10 \, \text{M} \, \text{NH}_4\text{Br}} \).

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