Questions: Construct a truth table for the statement. [ -p rightarrow(q wedge r) ] Fill in the blanks for the missing values in the table. p q r -p q^ r -p rightarrow(q wedge r) ------------------ T T T V v v T T F v v v T F T v checkmark v T F F 7 v v F T T v v 7 F T F v checkmark nabla F F T v nabla v F F F checkmark v 7

Construct a truth table for the statement.
[
-p rightarrow(q wedge r)
]

Fill in the blanks for the missing values in the table.

p  q  r  -p  q^ r  -p rightarrow(q wedge r)
------------------
T  T  T  V  v  v  
T  T  F  v  v  v  
T  F  T  v  checkmark  v  
T  F  F  7  v  v  
F  T  T  v  v  7  
F  T  F  v  checkmark  nabla  
F  F  T  v  nabla  v  
F  F  F  checkmark  v  7
Transcript text: Construct a truth table for the statement. \[ -p \rightarrow(q \wedge r) \] Fill in the blanks for the missing values in the table. \begin{tabular}{|c|c|c|c|c|c|c|} \hline p & q & r & -p & q^ r & \multicolumn{2}{|l|}{$-p \rightarrow(q \wedge r)$} \\ \hline T & T & T & V & v & v & \ \\ \hline T & T & F & $v$ & v & v & \ \\ \hline T & F & T & $v$ & $\checkmark$ & v & , \\ \hline T & F & F & 7 & v & v & \\ \hline F & T & T & $v$ & v & 7 & \\ \hline F & T & F & $v$ & $\checkmark$ & $\nabla$ & \\ \hline F & F & T & v & $\nabla$ & v & \\ \hline F & F & F & $\checkmark$ & v & 7 & \\ \hline \end{tabular}
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Solution

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Solution Steps

To construct a truth table for the statement \(-p \rightarrow (q \wedge r)\), we need to evaluate each component of the statement for all possible truth values of \(p\), \(q\), and \(r\). Specifically, we need to:

  1. Determine the truth value of \(-p\) (the negation of \(p\)).
  2. Determine the truth value of \(q \wedge r\) (the conjunction of \(q\) and \(r\)).
  3. Determine the truth value of \(-p \rightarrow (q \wedge r)\) (the implication from \(-p\) to \(q \wedge r\)).
Step 1: Construct the Truth Table

We evaluate the logical statement \(-p \rightarrow (q \wedge r)\) for all combinations of truth values for \(p\), \(q\), and \(r\). The possible combinations are:

  • \( (T, T, T) \)
  • \( (T, T, F) \)
  • \( (T, F, T) \)
  • \( (T, F, F) \)
  • \( (F, T, T) \)
  • \( (F, T, F) \)
  • \( (F, F, T) \)
  • \( (F, F, F) \)
Step 2: Calculate Intermediate Values

For each combination, we calculate:

  1. \( -p \)
  2. \( q \wedge r \)
  3. \( -p \rightarrow (q \wedge r) \)

The results for each combination are as follows:

  • For \( (T, T, T) \): \( -p = F \), \( q \wedge r = T \), \( -p \rightarrow (q \wedge r) = T \)
  • For \( (T, T, F) \): \( -p = F \), \( q \wedge r = F \), \( -p \rightarrow (q \wedge r) = T \)
  • For \( (T, F, T) \): \( -p = F \), \( q \wedge r = F \), \( -p \rightarrow (q \wedge r) = T \)
  • For \( (T, F, F) \): \( -p = F \), \( q \wedge r = F \), \( -p \rightarrow (q \wedge r) = T \)
  • For \( (F, T, T) \): \( -p = T \), \( q \wedge r = T \), \( -p \rightarrow (q \wedge r) = T \)
  • For \( (F, T, F) \): \( -p = T \), \( q \wedge r = F \), \( -p \rightarrow (q \wedge r) = F \)
  • For \( (F, F, T) \): \( -p = T \), \( q \wedge r = F \), \( -p \rightarrow (q \wedge r) = F \)
  • For \( (F, F, F) \): \( -p = T \), \( q \wedge r = F \), \( -p \rightarrow (q \wedge r) = F \)
Step 3: Summarize the Truth Table

The complete truth table is as follows:

\[ \begin{array}{|c|c|c|c|c|c|} \hline p & q & r & -p & q \wedge r & -p \rightarrow (q \wedge r) \\ \hline T & T & T & F & T & T \\ T & T & F & F & F & T \\ T & F & T & F & F & T \\ T & F & F & F & F & T \\ F & T & T & T & T & T \\ F & T & F & T & F & F \\ F & F & T & T & F & F \\ F & F & F & T & F & F \\ \hline \end{array} \]

Final Answer

The truth table for the statement \(-p \rightarrow (q \wedge r)\) is complete, with the final column indicating the truth values of the implication for each combination of \(p\), \(q\), and \(r\).

\(\boxed{\text{Truth table completed successfully.}}\)

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