Questions: Suppose the aqueous humor in a person's eye exerts a force of 0.315 N on the 1.3-cm² area of the cornea What is the pressure, in mm Hg, on the cornea? P=

Solution Steps

Pressure is defined as the force applied per unit area. The formula for pressure \( P \) is given by:

\[ P = \frac{F}{A} \]

where \( F \) is the force and \( A \) is the area.

Given:

• Force \( F = 0.315 \, \text{N} \)
• Area \( A = 1.3 \, \text{cm}^2 = 1.3 \times 10^{-4} \, \text{m}^2 \) (since \( 1 \, \text{cm}^2 = 10^{-4} \, \text{m}^2 \))

Substitute these values into the pressure formula:

\[ P = \frac{0.315}{1.3 \times 10^{-4}} = 2423.077 \, \text{Pa} \]

The conversion factor between pascals and mm Hg is \( 1 \, \text{mm Hg} = 133.322 \, \text{Pa} \).

Convert the pressure from pascals to mm Hg:

\[ P = \frac{2423.077}{133.322} \approx 18.176 \, \text{mm Hg} \]

Final Answer