Questions: Solve the equation by using the quadratic formula 3 k^2-k-3=0 Simplify answers. List multiple answers with a comma in bet

Solve the equation by using the quadratic formula
3 k^2-k-3=0

Simplify answers. List multiple answers with a comma in bet
Transcript text: Solve the equation by using the quadratic formula \[ 3 k^{2}-k-3=0 \] Simplify answers. List multiple answers with a comma in bet
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Solution

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Solution Steps

To solve the quadratic equation 3k2k3=03k^2 - k - 3 = 0 using the quadratic formula, we need to identify the coefficients aa, bb, and cc from the equation ax2+bx+c=0ax^2 + bx + c = 0. Then, we apply the quadratic formula k=b±b24ac2ak = \frac{-b \pm \sqrt{b^2 - 4ac}}{2a} to find the solutions for kk.

Solution Approach
  1. Identify the coefficients aa, bb, and cc from the equation.
  2. Use the quadratic formula to calculate the roots.
  3. Simplify the roots if possible.
Step 1: Identify the Coefficients

The given quadratic equation is 3k2k3=03k^2 - k - 3 = 0. From this equation, we identify the coefficients as follows:

  • a=3a = 3
  • b=1b = -1
  • c=3c = -3
Step 2: Calculate the Discriminant

We calculate the discriminant using the formula D=b24acD = b^2 - 4ac: D=(1)243(3)=1+36=37 D = (-1)^2 - 4 \cdot 3 \cdot (-3) = 1 + 36 = 37

Step 3: Apply the Quadratic Formula

Using the quadratic formula k=b±D2ak = \frac{-b \pm \sqrt{D}}{2a}, we find the two solutions: k1=(1)+3723=1+3761.1805 k_1 = \frac{-(-1) + \sqrt{37}}{2 \cdot 3} = \frac{1 + \sqrt{37}}{6} \approx 1.1805 k2=(1)3723=13760.8471 k_2 = \frac{-(-1) - \sqrt{37}}{2 \cdot 3} = \frac{1 - \sqrt{37}}{6} \approx -0.8471

Final Answer

The solutions to the equation 3k2k3=03k^2 - k - 3 = 0 are: k11.1805,k20.8471 \boxed{k_1 \approx 1.1805, \, k_2 \approx -0.8471}

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