Questions: 5.35 × 10^22 molecules O2 = LO2 STP

5.35 × 10^22 molecules O2 = LO2 STP
Transcript text: $5.35 \times 10^{22}$ molecules $\mathrm{O}_{2}=$ $\qquad$ LO_{2}@ STP
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Solution

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Solution Steps

Step 1: Determine the number of moles of \( \mathrm{O}_2 \)

To find the number of moles of \( \mathrm{O}_2 \) molecules, we use Avogadro's number, which is \( 6.022 \times 10^{23} \) molecules per mole.

\[ \text{Number of moles} = \frac{5.35 \times 10^{22} \text{ molecules}}{6.022 \times 10^{23} \text{ molecules/mole}} = 0.0888 \text{ moles} \]

Step 2: Calculate the volume of \( \mathrm{O}_2 \) at STP

At standard temperature and pressure (STP), 1 mole of any ideal gas occupies 22.414 liters. Therefore, the volume \( V \) of \( 0.0888 \) moles of \( \mathrm{O}_2 \) can be calculated as follows:

\[ V = 0.0888 \text{ moles} \times 22.414 \text{ L/mole} = 1.9900 \text{ L} \]

Final Answer

The volume of \( \mathrm{O}_2 \) at STP is:

\[ \boxed{1.99 \mathrm{L} \, \mathrm{O}_2 \, @ \, \mathrm{STP}} \]

Thus, the correct answer is (a) \( 1.99 \mathrm{L} \, \mathrm{O}_2 \, @ \, \mathrm{STP} \).

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